Question

我有一个Formview和一个UpdateView彼此冲突。他们应该一起工作，但不能以这种方式。每当我尝试使用UpdateView时，值就会通过FormView进行保存，这会导致其发送回表单验证错误

例如“具有该标题的视频已经存在”。

Forms.py ：

class BaseVideoUploadForm(forms.ModelForm):
    """
    Form for uploading videos using related to:

    :model: 'videos.Video'.
    """
    title = forms.CharField(
        widget=forms.TextInput(
            attrs={'placeholder': 'Blackjack shuffle procedures'}))
    description = forms.CharField(
        widget=forms.Textarea(attrs={'rows': 3}),
        help_text='A description of the content in this video.')
    category = forms.ModelChoiceField(
        queryset=Category.objects.all(),
        required=True)
    receiver = forms.ModelMultipleChoiceField(
        queryset=EmployeeType.objects.all(),
        required=True,
        widget=forms.CheckboxSelectMultiple,
        help_text='Employees in these groups will be able to view the video.')
    video_file = forms.FileField()
    thumbnail = forms.ImageField(required=False)

    class Meta:
        model = Video
        fields = (
            'title',
            'description',
            'receiver',
            'category',
            'video_file',
            'thumbnail',
        )
        widgets = {
            'date_time': forms.HiddenInput(),
            'sender': forms.HiddenInput(),
            'unviewed': forms.HiddenInput(),
            'viewed': forms.HiddenInput(),
        }

    def __init__(self, *args, **kwargs):
        super(BaseVideoUploadForm, self).__init__(*args, **kwargs)
        self.fields['receiver'].label = "Viewers"
        self.fields['receiver'].queryset = EmployeeType.objects.all()
        self.fields['category'].queryset = Category.objects.all()


class VideoUploadForm(BaseVideoUploadForm):
    send_notifications = forms.BooleanField(
        required=False,
        help_text='Send viewers a notification about the new video.')

    class Meta(BaseVideoUploadForm.Meta):
        fields = BaseVideoUploadForm.Meta.fields + ('send_notifications', )

FormView：

class VideoUploadView(FormView):
    form_class = VideoUploadForm
    success_url = '/videos'
    template_name = 'videos/video_form.html'

    def get(self, request, *args, **kwargs):
        form = self.form_class()
        return render(request, self.template_name, {'form': form})

    def post(self, request, *args, **kwargs):
        form = self.form_class(request.POST, request.FILES)
        form.instance.sender = self.request.user
        if form.is_valid():
            form.save()
            #  doing stuff

            form.save()
            messages.success(self.request, self.success_message)
            if request.is_ajax():
                return JsonResponse({'success': True, 'url': reverse('videos-home')})
            else:
                return redirect(self.success_url)
        else:
            if request.is_ajax():
                return JsonResponse({'success': False, 'error': form.errors})
            else:
                return render(request, self.template_name, {'form': form})

UpdateView ：

class VideoUpdateView(UpdateView):
    model = Video
    form_class = VideoUploadForm

Urls.py：

urlpatterns = [
    path('', views.VideoListView.as_view(), name='videos-home'),
    path('upload/', views.VideoUploadView.as_view(), name='videos-upload'),
    path('<int:pk>', VideoDetailView.as_view(), name='videos-detail'),
    path('<int:pk>/delete/', VideoDeleteView.as_view(), name='videos-delete'),
    path('<int:pk>/viewed/', views.mark_as_viewed, name='mark-as-viewed'),
    path('<int:pk>/update/', VideoUpdateView.as_view(), name='videos-update'),
    path('<int:pk>/notify', VideoNotificationView.as_view(), name='videos-notify'),
]

如何使UpdateView不依赖FormView？还是要使用FormView？ UpdateView似乎正在指向FormView。

如何使UpdateView与通用FormView一起使用

0 个答案: