Question

$(document).ready(function() {
    $("#list1").jqGrid({
        url: 'example1.php',
        /*balabala...*/
        gridComplete: function() {

        }
    });

    $("#list2").jqGrid({
        url: 'example2.php',
        /*balabala...*/
        gridComplete: function() {

        }
    });

    /*I want to do something here, but the above grids must be both complete first.*/
    Something...
});

我该怎么办？谢谢！

Answer 1

最简单的方法是将你的“东西”放在gridComplete回调中，但让两个回调检查另一个回调完成。这些方面的东西：

function do_something_wonderful() {
    // This is the awesome stuff that you want to
    // execute when both lists have loaded and finished.
    // ...
}

var one_done = false;
function done_checker() {
    if(one_done) {
        // The other one is done so we can get on with it.
        do_something_wonderful();
    }
    one_done = true;
}

$("#list1").jqGrid({
    //blah blah blah
    gridComplete: done_checker
});
$("#list2").jqGrid({
    //blah blah blah
    gridComplete: done_checker
});

这很好地扩展到两个以上的列表，只有几个小的修改：

使用var how_many_done = 0;代替one_done。
执行++how_many_done;代替one_done = true;并将其移至done_checker的顶部。
将if(one_done)替换为if(how_many_done == number_of_tasks)，其中number_of_tasks是您拥有的AJAX任务数量。

通用版本看起来像这样：

var number_of_tasks = 11; // Or how many you really have.
var how_many_done   = 0;
function done_checker() {
    ++how_many_done;
    if(how_many_done == number_of_tasks) {
        // All the AJAX tasks have finished so we can get on with it.
        do_something_wonderful();
    }
}

更好的版本会在闭包中结束状态：

var done_checker = (function(number_of_tasks, run_when_all_done) {
    var how_many_done = 0;
    return function() {
        ++how_many_done;
        if(how_many_done == number_of_tasks) {
            // All the AJAX tasks have finished so we can get on with it.
            run_when_all_done();
        }
    }
})(do_something_wonderful, 11);

Answer 2

您当前应该使用jquery deferred objects。

如何确认何时完成多个AJAX通话？

2 个答案: