Question

也许这是一个简单的问题，但我不知道该怎么做。我有2个SQL查询，两者几乎相同，仅在WHERE子句中有所不同。每个查询返回1个SUM编号。我需要从两个查询中获取结果，并使用它来创建1个称为“ RESULT”的列，该列将计算查询的结果。

1个查询：

SELECT SUM(a.ACC_NOMINAL_AMOUNT) AS RESULT
        FROM ACCOUNTS a 
        INNER JOIN PARTIES p
        ON a.PT_KEY = p.PT_KEY
        INNER JOIN ACCOUNT_COLLATERALS c
        ON c.ACC_KEY = a.ACC_KEY
        INNER JOIN COLLATERALS co
        on c.COLT_KEY = co.COLT_KEY
        INNER JOIN COLLATERAL_PORTFOLIOS por
        ON co.COLTPTF_KEY = por.COLTPTF_KEY
        WHERE co.COLTPTF_KEY = '261' AND 
        co.COLT_DELETED_FLAG = 'N' AND 
        a.ACC_CLOSE_FLAG = 'N' 
        AND  co.COLT_SHORTENING_COEFFICIENT = 82

2个查询：

SELECT SUM(a.ACC_NOMINAL_AMOUNT) AS RESULT
        FROM ACCOUNTS a 
        INNER JOIN PARTIES p
        ON a.PT_KEY = p.PT_KEY
        INNER JOIN ACCOUNT_COLLATERALS c
        ON c.ACC_KEY = a.ACC_KEY
        INNER JOIN COLLATERALS co
        on c.COLT_KEY = co.COLT_KEY
        INNER JOIN COLLATERAL_PORTFOLIOS por
        ON co.COLTPTF_KEY = por.COLTPTF_KEY
        WHERE co.COLTPTF_KEY = '261' AND 
        co.COLT_DELETED_FLAG = 'Y' AND 
        a.ACC_CLOSE_FLAG = 'Y' 
        AND  co.COLT_SHORTENING_COEFFICIENT = 82

让我们说第一个查询返回SUM值10，第二个返回5。因此，我需要查询将返回带有15的RESULT列。

也许编写此查询有更有效的方法，因为它仅在两个参数的WHERE子句中有所不同。

感谢帮助

Answer 1

您可以轻松组合条件：

SELECT SUM(a.ACC_NOMINAL_AMOUNT)
FROM . . .
WHERE co.COLTPTF_KEY = '261' AND 
      co.COLT_SHORTENING_COEFFICIENT = 82 AND
      (co.COLT_DELETED_FLAG, a.ACC_CLOSE_FLAG) IN ( ('N', 'N'), ('Y', 'Y') )

Answer 2

这应该可以完成工作：

SELECT SUM(a.ACC_NOMINAL_AMOUNT) AS RESULT
FROM ACCOUNTS a 
INNER JOIN PARTIES p ON a.PT_KEY = p.PT_KEY
INNER JOIN ACCOUNT_COLLATERALS c ON c.ACC_KEY = a.ACC_KEY
INNER JOIN COLLATERALS co ON c.COLT_KEY = co.COLT_KEY
INNER JOIN COLLATERAL_PORTFOLIOS por ON co.COLTPTF_KEY = por.COLTPTF_KEY
WHERE 
    co.COLTPTF_KEY = '261' 
    AND (a.ACC_CLOSE_FLAG, co.COLT_DELETED_FLAG) IN ( ('Y', 'Y'), ('N', 'N') )
    AND  co.COLT_SHORTENING_COEFFICIENT = 82

您可以使用条件聚合一次获得3个结果：

SELECT 
    SUM(CASE WHEN a.ACC_CLOSE_FLAG = 'N' AND co.COLT_DELETED_FLAG = 'N' 
        THEN a.ACC_NOMINAL_AMOUNT END) AS RESULT_N,
    SUM(CASE WHEN a.ACC_CLOSE_FLAG = 'Y' AND co.COLT_DELETED_FLAG = 'Y' 
        THEN a.ACC_NOMINAL_AMOUNT END) AS RESULT_Y,
    SUM(a.ACC_NOMINAL_AMOUNT) AS RESULT
FROM ACCOUNTS a 
INNER JOIN PARTIES p ON a.PT_KEY = p.PT_KEY
INNER JOIN ACCOUNT_COLLATERALS c ON c.ACC_KEY = a.ACC_KEY
INNER JOIN COLLATERALS co ON c.COLT_KEY = co.COLT_KEY
INNER JOIN COLLATERAL_PORTFOLIOS por ON co.COLTPTF_KEY = por.COLTPTF_KEY
WHERE 
    co.COLTPTF_KEY = '261' 
    AND (a.ACC_CLOSE_FLAG, co.COLT_DELETED_FLAG) IN ( ('Y', 'Y'), ('N', 'N') )
    AND  co.COLT_SHORTENING_COEFFICIENT = 82

SQL将两个SUM查询的结果用于一个查询

2 个答案: