Question

如果我的自定义资源提供程序希望将自定义失败消息返回给ARM，那么我的响应主体应该是什么？我有一个由JavaScript Azure函数支持的自定义资源提供程序我尝试了以下

 body = {
       error: {
            code: "Failed",
            message: "A custom error message'."
        }
    };
httpStatus = 200;

 context.res = {
            status: httpStatus,
            headers: {
                'Content-Type': 'application/json'
              },
            body: body
        };

ARM模板部署失败，并显示错误-

{
    "error": {
        "code": "ResourceDeploymentFailure",
        "message": "The response for resource had empty or invalid content."
    }

我也尝试过

 body = {
       properties: {
       provisioningState: "Failed",
       error: {
            code: "Failed",
            message: "A custom error message'."
        }
       }
    };
httpStatus = 200;

 context.res = {
            status: httpStatus,
            headers: {
                'Content-Type': 'application/json'
              },
            body: body
        };

ARM模板部署失败并显示错误

"The resource operation completed with terminal provisioning state 'Failed"

我希望ARM模板部署失败，并显示一条自定义错误消息，我从Azure函数返回“自定义错误消息”。

编辑：

这是我的ARM模板

{
  "$schema": "https://schema.management.azure.com/schemas/2015-01-01/deploymentTemplate.json#",
  "contentVersion": "1.0.0.0",
  "parameters": {
    "resourcePrefix": {
      "type": "string",
      "defaultValue": "prfx-",
      "maxLength": 6,
      "metadata": {
        "description": "The prefix of HLF resource."
      }
    },
    "randomGuid": {
      "defaultValue": "[newGuid()]",
      "type": "string",
      "metadata": {
        "description": "New random GUID"
      }
    }
  },
  "variables": {
    "funcName": "[concat(parameters('resourcePrefix'), substring(parameters('randomGuid'), 0, 5))]",
    "myResourceProvider": "my-custom-provider",
    "location": "[resourceGroup().location]"
  },
  "resources": [
    {
      "apiVersion": "2018-09-01-preview",
      "type": "Microsoft.CustomProviders/resourceProviders",
      "name": "[variables('myResourceProvider')]",
      "location": "[variables('location')]",
      "properties": {
        "resourceTypes": [
          {
            "name": "deploy",
            "routingType": "Proxy",
            "endpoint": "<azure-func-url>"
          }
        ]
      }
    },
    {
      "apiVersion": "2018-09-01-preview",
      "type": "Microsoft.CustomProviders/resourceProviders/deploy",
      "name": "[concat(variables('myResourceProvider'), '/', variables('funcName'))]",
      "location": "[variables('location')]",
      "dependsOn": [
        "[concat('Microsoft.CustomProviders/resourceProviders/',variables('myResourceProvider'))]"
        ]      
    }
  ],
  "outputs": {
  }
}

Answer 1

自定义提供程序当前不支持按原样代理错误消息。自定义错误消息将作为详细信息嵌套在标准消息下。

但是，似乎有一个错误正在阻止该错误通过ARM模板的传播。这应该尽快解决！

Answer 2

@jjbfour是正确的。自定义消息嵌套在传播的消息中的“下游”标签下。但这对我很好。以下作品

seen

我之前犯的错误没有正确设置HTTP状态。

Azure自定义资源提供程序-ARM模板的自定义错误消息

2 个答案: