我有一个datetime
字符串,将从中创建一个start_time
和end_time
变量。
预期输出:
start_time
应该是从现在开始的2天,从datetime
字符串开始的时间,而end_time
应该是从start_time
开始的3小时。
代码
<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.18.1/moment.min.js"></script>
<script>
const time = "2019-12-13T05:30:00+08:00"
const date = moment(time);
const h = date.hour();
const m = date.minutes();
const s = date.seconds();
const from = moment().add(2, 'days');
var start_time = from.clone().hour(h).minute(m).second(s);
var end_time = start_time.clone().add(3, 'hours');
// start_time = start_time.toISOString();
// end_time = end_time.toISOString();
console.log(start_time); // Expected: "2019-12-15T05:30:00+08:00"
console.log(end_time); // Expected: "2019-12-15T08:30:00+08:00"
</script>
预期结果:
开始时间:“ 2019-12-15T05:30:00 + 08:00”
结束时间:“ 2019-12-15T08:30:00 + 08:00”
当前结果:
开始时间:“ 2019-12-14T21:30:00.604Z”
结束时间:“ 2019-12-15T00:30:00.604Z”
在这种情况下,如何正确格式化日期以达到预期效果的任何想法?
答案 0 :(得分:2)
这是因为您使用的是不同的时区。输入为+8时区,输出为UTC
如果添加了.format()
,您将看到实际上具有正确的值。
<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.18.1/moment.min.js"></script>
<script>
const time = "2019-12-13T05:30:00+08:00"
const date = moment(time);
const h = date.hour();
const m = date.minutes();
const s = date.seconds();
const from = moment().add(2, 'days');
var start_time = from.clone().hour(h).minute(m).second(s);
var end_time = start_time.clone().add(3, 'hours');
// start_time = start_time.toISOString();
// end_time = end_time.toISOString();
// added .format()
console.log(start_time.format()); // Expected: "2019-12-15T05:30:00+08:00"
console.log(end_time.format()); // Expected: "2019-12-15T08:30:00+08:00"
</script>
答案 1 :(得分:1)
尝试这样:
var start_time:moment().add(2,'days');
var end_time:moment().add(2,'days').add(3,'hours')