Question

有人可以告诉我，我应该如何创建类似[here] [1]的listview。

问题：如何在我的代码中实现具有图标，文件名和文件大小的外观和感觉，同时在每个文件对象上看起来干净简单，如示例中所示链接[这里] [2] ??

有人可以指导这件事，因为我在android / java中比较新...谢谢

Answer 1

问题2：为什么我的列表视图目录时出错尽管有这个要处理，但是空的我的xml中的“空”

你记得列出你的列表视图吗？：

@id/android:list

如果你能够进一步帮助请清除问题1 ，那么它更清晰简洁你想要的东西。

<强>更新

列表视图的ID应为：@id/android:list

texview的ID应为：@id/android:empty

Answer 2

请参阅以下url for how to implement custom listview

<强>更新

public static class VideoInfo   {
        public String name = "";
        public String size= "";
        public String path = "";//add any more variables of which you want info
    }

然后你在哪里创建arraylist，即getVideoFiles()创建这个类的对象声明ArrayList<VideoInfo> videoItems;

private void getVideoFiles(File[] videoList) 
 {
      videoItems = new ArrayList<VideoInfo>();

      for (int i = 0; i < videolist.length; i++) 
      {
        File mfile = videoList[i];
      String path = mfile.getPath();
      path = path.substring(path.lastIndexOf("/", path.indexOf("."));
      VideoInfo model = new VideoInfo();
      model.name = path;
      model.size = mfile.length();

      videoItems.add(model);
      }

      setListAdapter(new ListViewAdapter(this, R.layout.row, videoItems));  
 }

现在在你的适配器中传递arraylist的这个对象以及如何在listview中设置变量已在上面的链接中给出

Answer 3

您尚未创建自定义适配器以将布局合并到代码列表视图中。这是你可以使用的东西

private class ListViewAdapter extends ArrayAdapter<Object> {
        private ArrayList<Object> items;

        public ListViewAdapter(Context context, int textViewResourceId,
                ArrayList<Object> items) {
            super(context, textViewResourceId, items);
            this.items = items;

        }

        @Override
        public View getView(int position, View convertView, ViewGroup parent) {
            View v = convertView;
            Object info = items.get(position);
            if (v == null) {
                LayoutInflater vi = (LayoutInflater) getSystemService(Context.LAYOUT_INFLATER_SERVICE);
                v = vi.inflate(R.layout.row, null);
            }

            if (info != null) {
                ImageView imView = (ImageView) v.findViewById(R.id.icon);
                TextView txtname =(TextView) v.findViewById(R.id.toptext);
                TextView txtAddr = (TextView) v.findViewById(R.id.bottomtext);
                //set image and set text as you like
            }
            return v;
        }
    }

希望这可以提供帮助。

Answer 4

首先创建要为列表中的每一行显示的布局，然后将BaseAdapter类扩展为自定义列表。此类包含getView方法，可以根据需要多次复制列表中的行。

类HighScoreAdapter扩展了BaseAdapter { / * layout inflater将您的XML布局转换为View以在每行列表中呈现。* / private LayoutInflater minflator = LayoutInflater.from（HighScoreList.this）; ViewHolder holder;

    @Override
    public Object getItem(int position)
    {
        return position;
    }

    @Override
    public long getItemId(int position)
    {
        return position;
    }
    boolean toRemove = false;
    @Override
    public View getView(int position, View convertView, ViewGroup parent)
    {
                    /* first time is null */
        if (convertView == null )
        {
            convertView = minflator.inflate(R.layout.highscorelist, null);
            holder = new ViewHolder();
            holder.rank = (TextView) convertView.findViewById(R.id.user_id);
            holder.username = (EditText) convertView.findViewById(R.id.user_nameedit);
            holder.time = (TextView) convertView.findViewById(R.id.user_time);
            convertView.setTag(holder);
        }
        else
        {
            holder  =   (ViewHolder) convertView.getTag();
        }

        holder.rank.setText(String.valueOf(position+1)+".");

        /* returns the view for next row as layout will be same i.e. this increases the your list's scrolling and working faster even though your list contains thousands of Entry*/
        return convertView;
    }
             /* this class is to make reference to your child views of your layout by using this you can set your child views properties and Listeners acording to your need.*/
    class ViewHolder
    {
        TextView rank;
        EditText username;
        TextView time;
    }

}

我希望这完全解决你的问题.. :)

Answer 5

将此方法添加到您的代码中，如果您收到任何错误或异常，请告知我们。

    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        View v = convertView;
        Object info = items.get(position);
        if (v == null) {
            LayoutInflater vi = (LayoutInflater) getSystemService(Context.LAYOUT_INFLATER_SERVICE);
            v = vi.inflate(R.layout.row, null);
        }

        if (info != null) {
            ImageView imView = (ImageView) v.findViewById(R.id.icon);
            TextView txtname =(TextView) v.findViewById(R.id.toptext);
            TextView txtAddr = (TextView) v.findViewById(R.id.bottomtext);
            //set image and set text as you like

               imview.setImageBitmap(IMAGE YOU WANT TO SET AAS ICON);

               txtname.setText(FILENAME YOU WANT TO SET);

               txtadr,setText(FILESIZE YOU WANT TO SET);

              // Better you take each info filename,filesize and icon in a arraylist and set them 

        }


        return v;
    }

如何创建我的上面的listview看起来更专业？

5 个答案: