Question

我有一个包含2个字段timestamp and count的表。该表包含自2016年11月以来的数据。

我必须设置一个查询，该查询将汇总所有年份的YTD sum(count)。我没有使用日历年的定义，而是使用11月至10月（下一年）。这不应该理想地改变逻辑

2017: 11/01/2016-10/31/2017;
2018: 11/01/2017-10/31/2018;
2019: 11/01/2018-10/31/2019; 
2020: 11/01/2019-10/31/2020

我想要一个查询，该查询将在任何给定的日期以11月1日为开始日期计算年初至今的总和。我尝试了这个查询

select ytd_bucket
,sum(count_field) sum
from
(
select 
timestamp_field,
count_field,
CASE 
WHEN DATE(timestamp_field,"America/Los_Angeles") >= '2019-11-01' THEN '2020'
WHEN DATE(timestamp_field,"America/Los_Angeles") BETWEEN '2018-11-01' AND CAST(CONCAT('2019-',FORMAT_DATE('%m-%d', DATE(CURRENT_TIMESTAMP(),"America/Los_Angeles"))) AS DATE) THEN '2019'
WHEN DATE(timestamp_field,"America/Los_Angeles") BETWEEN '2017-11-01' AND CAST(CONCAT('2018-',FORMAT_DATE('%m-%d', DATE(CURRENT_TIMESTAMP(),"America/Los_Angeles"))) AS DATE) THEN '2018'
WHEN DATE(timestamp_field,"America/Los_Angeles") BETWEEN '2016-11-01' AND CAST(CONCAT('2017-',FORMAT_DATE('%m-%d', DATE(CURRENT_TIMESTAMP(),"America/Los_Angeles"))) AS DATE) THEN '2017'
ELSE NULL END as YTD_bucket
from table
)
group by 1

以上查询未汇总数字为年初至今水平。对于2020年之前的年份（ytd_bucket），该查询将汇总整个年份。

Answer 1

从每天汇总开始：

select date(timestamp_field, 'America/Los_Angeles') as dte,
       count(*)
from table
group by dte;

然后，对于年初至今，您要添加一年并获取日期：

select dte,
       count(*),
       sum(count(*)) over (partition by extract(year from date_add(dte, interval 1 month))
                           order by min(timestamp_field)
                          ) as running_cnt
from (select t.*,
             date(timestamp_field, 'America/Los_Angeles') as dte
      from t
     ) t
group by dte;

如何动态累计YTD量度

1 个答案: