是否有回调函数或一种方法来知道Navigator.of(context).pop()
的动画返回到先前的屏幕已完成?目前我正在使用await Future.delayed(Duration(milliseconds: 500));
完成此操作。有更好的方法吗?
我将其用于showModalBottomSheet(useRootNavigator: true)
,然后Navigator.pop()
关闭底部工作表,然后推一条新路线。
代码:
Navigator.of(context).pop();
await Future.delayed(Duration(milliseconds: 500));
Navigator.of(context).push(...) // push new screen
答案 0 :(得分:1)
您可以尝试
# -*- mode: python ; coding: utf-8 -*-
block_cipher = None
a = Analysis(['main.py'],
pathex=['C:\\Users\\WallaceSilva\\Desktop\\pyinstaller'],
binaries=[],
datas=[],
hiddenimports=[],
hookspath=[],
runtime_hooks=[],
excludes=[],
win_no_prefer_redirects=False,
win_private_assemblies=False,
cipher=block_cipher,
noarchive=False)
pyz = PYZ(a.pure, a.zipped_data,
cipher=block_cipher)
exe = EXE(pyz,
a.scripts,
[],
exclude_binaries=True,
name='setup',
debug=False,
bootloader_ignore_signals=False,
strip=False,
upx=True,
console=True )
coll = COLLECT(exe,
a.binaries,
a.zipfiles,
a.datas,
strip=False,
upx=True,
upx_exclude=[],
name='setup')
答案 1 :(得分:1)
按一条路线已经维护了一个Future,当弹出发生时,它会完成。这意味着您可以执行以下操作:
Navigator.of(context).pushNamed('/someRoute').then((completion){
//do something
});
名为完成的参数也可以是要从显示的屏幕中检索的任何数据。例如,假设我有一个群聊,我想向其中添加一个用户。为此,我想显示一个屏幕,允许我选择一个用户,然后将该用户传递回上一个屏幕。
Navigator.of(context).pushNamed('/InviteToChatScreen').then((object) {
if (object != null) {
var user = object as User;
//add them to the chat
}
});
答案 2 :(得分:0)
您可以尝试使用 RouteAware,它提供的覆盖方法很少
didPop() → void
Called when the current route has been popped off.
didPopNext() → void
Called when the top route has been popped off, and the current route shows up.
didPush() → void
Called when the current route has been pushed.
didPushNext() → void
https://api.flutter.dev/flutter/widgets/RouteAware-class.html