Question

我尝试使用模拟器测试Firestore安全规则，但始终会发生超时错误... 请让我知道您是否有相同的现象或解决方法。

测试结果

启动模拟器

% firebase serve --only firestore

运行测试

% yarn test
yarn run v1.19.2
$ jest
 FAIL  tests/firestore.test.ts (7.123s)
  Firestore Security Rule
    ✕ sample1 (5044ms)

  ● Firestore Security Rule › sample1

    : Timeout - Async callback was not invoked within the 5000ms timeout specified by jest.setTimeout.Timeout - Async callback was not invoked within the 5000ms timeout specified by jest.setTimeout.Error:

      30 |   });
      31 |
    > 32 |   test("sample1", async () => {
         |   ^
      33 |     const db = createAuthApp();
      34 |     const user = usersRef(db).doc("test");
      35 |     await firebase.assertSucceeds(user.set({ name: "John" }));

      at new Spec (node_modules/jest-jasmine2/build/jasmine/Spec.js:116:22)
      at Suite.<anonymous> (tests/firestore.test.ts:32:3)
      at Object.<anonymous> (tests/firestore.test.ts:16:1)

Test Suites: 1 failed, 1 total
Tests:       1 failed, 1 total
Snapshots:   0 total
Time:        8.038s
Ran all test suites.
error Command failed with exit code 1.
info Visit https://yarnpkg.com/en/docs/cli/run for documentation about this command.

环境

※由于示例，Firestore安全规则允许所有操作

■firestore.test.ts

import * as firebase from "@firebase/testing";
import * as fs from "fs";

const PROJECT_ID = "firestore-rule-test";
const RULES_PATH = "firestore.rules";

// Create Firestore app with auth
const createAuthApp = (auth?: object): firebase.firestore.Firestore => {
  return firebase
    .initializeTestApp({ projectId: RULES_PATH, auth: auth })
    .firestore();
};

const usersRef = (db: firebase.firestore.Firestore) => db.collection("user");

describe("Firestore Security Rule", () => {
  beforeAll(async () => {
    await firebase.loadFirestoreRules({
      projectId: PROJECT_ID,
      rules: fs.readFileSync(RULES_PATH, "utf8")
    });
  });

  afterEach(async () => {
    await firebase.clearFirestoreData({ projectId: PROJECT_ID });
  });

  afterAll(async () => {
    await Promise.all(firebase.apps().map(app => app.delete()));
  });

  test("sample1", async () => {
    const db = createAuthApp();
    const user = usersRef(db).doc("test");
    await firebase.assertSucceeds(user.set({ name: "John" }));
    await firebase.assertSucceeds(user.get());
  });
});;

Answer 1

在您的createAuthApp()函数中，您正在使用项目ID为RULES_PATH初始化测试应用程序，但是在您的测试中，您正在使用项目PROJECT_ID来加载安全规则。

更改

.initializeTestApp({ projectId: RULES_PATH, auth: auth })

到

.initializeTestApp({ projectId: PROJECT_ID, auth: auth })

应该解决您的问题。

万一无法解决问题，您可以使用--testTimeout=<number of ms>将Jest超时更改为5秒以上，以使测试有更多时间完成。

最后，为清楚起见，考虑将createAuthApp重命名为createFirestoreInstance，因为“创建身份验证”暗示与FirebaseAuth类有关。

尝试使用模拟器测试Firestore安全规则时，总是会发生超时错误

1 个答案: