教授对Python作业的回答将无法运行：TypeError：__init __（）缺少1个必需的位置参数：'gender'

Question

我确定之前已经有人问过这个问题，但是目前我还不能理解其他问题是如何回答我的。有人可以用此代码解释问题吗？我看不到：

{ node: { title: 'Default Title' } }

PyCharm返回的错误是：

class Person:
    name = ''
    age = 0
    gender = ''

    def __init__(self, name, age, gender):
        self.name = name
        self.age = age
        self.gender = gender


class Employee(Person):
    title = ''
    salary = 0

    def __init__(self, name, age, gender, title, salary):
        Person.__init__(name, age, gender)
        self.title = title
        self.salary = salary


George = Employee("George", 30, "Male", "Manager", 50000)
print("George's info is: Name is %s, Age is %d, Gender is %s, Title is %s, and Salary is %d" % (
George.name, George.age, George.gender, George.title, George.salary))

Answer 1

更改此行：

        Person.__init__(name, age, gender)

收件人：

        Person.__init__(self, name, age, gender)

说明：Person.__init__方法采用四个参数，第一个参数是要初始化的对象的self参数。通常，self参数是特殊的，因为它自动获取调用该方法的对象的值。但是，由于Person是类，而不是对象，因此在这种情况下不会在对象上调用该方法，因此必须将self参数作为显式参数传递。

通常写成这样：

        super().__init__(name, age, gender)

这看起来有些奇怪，但是它避免了不必要地再次写入父类的名称，并且当一个类具有两个超类时，它可以正常工作。

Answer 2

需要更改的是对类Person.__init__(name, age, gender)中的Employee的调用，定义为def __init__(self, name, age, gender):
您的正确代码是-

class Person:
    name = ''
    age = 0
    gender = ''

    def __init__(self, name, age, gender):
        self.name = name
        self.age = age
        self.gender = gender


class Employee(Person):
    title = ''
    salary = 0

    def __init__(self, name, age, gender, title, salary):
        Person.__init__(self, name, age, gender)
        self.title = title
        self.salary = salary


George = Employee("George", 30, "Male", "Manager", 50000)
print("George's info is: Name is %s, Age is %d, Gender is %s, Title is %s, and Salary is %d" % (
George.name, George.age, George.gender, George.title, George.salary))

这将使您的输出为-

George's info is: Name is George, Age is 30, Gender is Male, Title is Manager, and Salary is 50000