我的熊猫文件结构如下(python 3)
Particulars AMT AA(AED) QP 7 WP 8 ST 9 AB(USD) RR 6 RA 8 DA(INR) DRS 5 DRW 3 UTS 6
我希望输出如下(python 3)
Particulars AMT LOG AA(AED) AA(AED) QP 7 WP 8 ST 9 AB(USD) AB(USD) RR 6 RT 8 DA(INR) DA(INR) DRS 5 DRW 3 UTS 6
答案 0 :(得分:1)
尝试一下:
df['LOG'] = None
df['LOG'] = df[df['Particulars'].str.contains(r'\w+\(\w+\)')].reindex(range(0,len(df))).fillna('')
输出:
Particulars AMT LOG
0 AA(AED) AA(AED)
1 QP 7
2 WP 8
3 ST 9
4 AB(USD) AB(USD)
5 RR 6
6 RA 8
7 DA(INR) DA(INR)
8 DRS 5
9 DRW 3
10 UTS 6
答案 1 :(得分:0)
temp=df.Particulars.fillna("0")
df['LOG'] = pd.np.where(temp.str.contains("0"),"",
pd.np.where(temp.str.contains(r'\(\w+\)'), df['Particulars'],''))
df