Question

按下按钮时有一个UIEvent，在NSLog中，它返回为：

<UITouchesEvent: 0x4b13210> timestamp: 3764.51 touches: {(
    <UITouch: 0x4b1edf0> phase: Began tap count: 1 window: <UIWindow: 0x4b342b0; frame = (0 0; 320 480); opaque = NO; autoresize = RM+BM; layer = <CALayer: 0x4b34400>> view: <UIView: 0x4b356c0; frame = (0 20; 320 460); autoresize = W+H; layer = <CALayer: 0x4b33990>> location in window: {121, 377} previous location in window: {121, 377} location in view: {121, 357} previous location in view: {121, 357}
)}

我如何获得某些信息，例如图层框架。

Answer 1

按下按钮时，与事件关联的所有触摸都将作为一组UITouch对象传递给函数“fntButtonPress”。你需要做的是找到你的目标。在此示例中，根据您的请求，向您展示如何从触摸设置中获取图层。

[YourButton addTarget:self action:@selector(fntButtonPress:event:) forControlEvents:UIControlEventTouchUpInside];

- (void) fntButtonPress:(id)sender event:(id)event {
    NSSet *touches = [event allTouches];
    UITouch *touch = [touches anyObject];
    CALayer *touchedLayer = [touch view].layer;
}

Answer 2

UIEvent对象有一个UITouch的集合。通过UITouch对象，您可以访问window和view属性，这些属性又可以访问相应的框架，图层等。

参考文献：UIEvent，UITouch

我如何从触摸事件中获取信息？

2 个答案: