ViewModel不随数据更改而更新

时间:2019-12-09 12:59:03

标签: android kotlin mvvm observable

因此,这是我第一次在Android中使用架构组件。我正在尝试创建一个ViewModel,它将继续返回UI元素可以使用的最新位置。我已经创建了一个如下的viewModel:

    class LocationViewModel(application: Application) : AndroidViewModel(application) {
        val currentLocation = MutableLiveData<Location?>()

        init {
            val ctx = getApplication<Application>().applicationContext
            val fusedLocationProvider = LocationServices.getFusedLocationProviderClient(ctx)

            val locationRequest = LocationRequest.create()
            locationRequest.priority = LocationRequest.PRIORITY_BALANCED_POWER_ACCURACY
            locationRequest.interval = 5000
            locationRequest.fastestInterval = 2000

            val builder = LocationSettingsRequest.Builder().addLocationRequest(locationRequest)
            val client = LocationServices.getSettingsClient(ctx)

            client.checkLocationSettings(builder.build()).addOnFailureListener {
                currentLocation.postValue(null)
            }

            val locationCallback = object : LocationCallback() {
                override fun onLocationResult(p0: LocationResult?) {
                    super.onLocationResult(p0)
                    p0 ?: return
                    currentLocation.postValue(p0.lastLocation)
                }
            }

            fusedLocationProvider.requestLocationUpdates(
                locationRequest,
                locationCallback,
                Looper.getMainLooper()
            )
        }
    }

我在一个活动中观察了这个ViewModel,

    class MainActivity : AppCompatActivity() {
        private lateinit var locationText: TextView

        override fun onCreate(savedInstanceState: Bundle?) {
            super.onCreate(savedInstanceState)
            setContentView(R.layout.activity_main)

            locationText = findViewById(R.id.locationText)

            val location = ViewModelProviders.of(this)[LocationViewModel::class.java]
            location.currentLocation.observe(this, Observer { resutlLocation: Location? ->
                locationText.text =
                    if (resutlLocation != null) "Lat: ${resutlLocation.latitude} Long: ${resutlLocation.longitude}" else "Null"
            })
        }
    }

TextView甚至不会更新一次。应该如何做这些事情?我究竟做错了什么?

1 个答案:

答案 0 :(得分:0)

在View中,像这样在View模型中创建函数。

fun initdata() {

    val ctx = getApplication<Application>().applicationContext
    val fusedLocationProvider = LocationServices.getFusedLocationProviderClient(ctx)

    val locationRequest = LocationRequest.create()
    locationRequest.priority = LocationRequest.PRIORITY_BALANCED_POWER_ACCURACY
    locationRequest.interval = 5000
    locationRequest.fastestInterval = 2000

    val builder = LocationSettingsRequest.Builder().addLocationRequest(locationRequest)
    val client = LocationServices.getSettingsClient(ctx)

    client.checkLocationSettings(builder.build()).addOnFailureListener {
        currentLocation.postValue(null)
    }

    val locationCallback = object : LocationCallback() {
        override fun onLocationResult(p0: LocationResult?) {
            super.onLocationResult(p0)
            p0 ?: return
            currentLocation.postValue(p0.lastLocation)
        }
    }

    fusedLocationProvider.requestLocationUpdates(
        locationRequest,
        locationCallback,
        Looper.getMainLooper()
    )
}

然后像这样使用

  val viewModel = ViewModelProviders.of(this)[LocationViewModel::class.java]
  viewModel.initdata()

编辑1

您可以像这样懒惰初始化

private val users:MutableLiveData<Location?> by lazy {
    MutableLiveData().also {
      initdata()
    }
}

更多详细信息,请参见ViewModel