Question

我的数据库中有下表：

Invoice_no  Type  Amount
------------------------
INV001      ET101  4000
INV001      ET102  4000
INV002      ET101  3400
INV002      ET102  3400
INV003      ET101  2300

我只想显示同时具有ET101和ET102类型的发票编号行。没有两种输入类型的任何发票号都不会显示。请提出在SQL Server中使用查询的最佳方法。

建议查询后的结果将是：

Invoice_no  Type  Amount
------------------------
INV001      ET101  4000
INV001      ET102  4000
INV002      ET101  3400
INV002      ET102  3400

INV003仅包含ET101，因此不会显示。

Answer 1

尝试一下：

tbl(Invoice_no,  Type,  Amount)


select *
from tbl a
where a.Type  = 'ET101'
and exists (
  select 1
  from tbl b
  where b.Type  = 'ET102' and a.Invoice_no = b.Invoice_no
)

Answer 2

您可以尝试以下查询

SELECT *
FROM Invoice
WHERE Invoice_no IN (
  SELECT distinct INVOICE_NO FROM Invoice
  WHERE TYPE = 'ET101'
  INTERSECT
  SELECT distinct INVOICE_NO FROM Invoice
  WHERE TYPE = 'ET102'
)

Answer 3

如果您都希望行，那么我建议：

select i.*
from invoice i
where (i.type = 'ET101' and
       exists (select 1
               from invoice i2
               where i2.invoice_no = i.invoice_no and
                     i2.type = 'ET102'
              )
      ) or
      (i.type = 'ET102' and
       exists (select 1
               from invoice i2
               where i2.invoice_no = i.invoice_no and
                     i2.type = 'ET101'
              )
      ) ;

您实际上可以将此逻辑缩短为：

select i.*
from invoice i
where i.type in ('ET101', 'ET102') and
      exists (select 1
              from invoice i2
              where i2.invoice_no = i.invoice_no and
                    i2.type in ('ET101', 'ET102') and
                    i2.type <> i.type
              );

如果您只需要发票编号，那么我建议汇总：

select i.invoice_no
from invoice i
where i.type in ('ET101', 'ET102') 
group by i.invoice_no
having count(distinct i.type) = 2;

根据SQL Server中两个条件的可用性显示记录

3 个答案: