Question

下面的代码获取该区域的当前时间和时区

.save()

现在是下午1:01（在输入时）

我需要帮助的是在代码中实现一项功能，该功能可以检查当前时间是否已过去，例如1:00 PM

但是我什至不知道从哪里开始，你能帮我吗？

Answer 1

使用Java 8+ Time API类LocalTime：

LocalTime refTime = LocalTime.of(13, 0); // 1:00 PM

// Check if now > refTime, in default time zone
LocalTime now = LocalTime.now();
if (now.isAfter(refTime)) {
    // passed
}

// Check if now >= refTime, in pacific time zone
LocalTime now = LocalTime.now(ZoneId.of("America/Los_Angeles"))
if (now.compareTo(refTime) >= 0) {
    // passed
}

Answer 2

我看到它已经用Time回答了，但是作为一个教学要点，如果您真的想使用Date，则可以执行以下操作：

public static void main(String[] args) {
    Date date = new Date();
    DateFormat df = new SimpleDateFormat("HH:mm:ss");
    df.setTimeZone(TimeZone.getDefault());
    System.out.println("Time: " + df.format(date));

    //If you print the date you'll see how it is formatted
    //System.out.println(date.toString());

    //So you can just split the string and use the segment you want
    String[] fullDate = date.toString().split(" ");

    String compareAgainstTime = "01:00PM";

    System.out.println(isPastTime(fullDate[3],compareAgainstTime));
    }

public static boolean isPastTime(String currentTime, String comparedTime) {
    //We need to make the comparison time into the same format as the current time: 24H instead of 12H:
    //then we'll just convert the time into only minutes to that we can more easily compare;
    int comparedHour = comparedTime[-2].equals("AM") ? String.valueOf(comparedTime[0:2]) : String.valueOf(comparedTime[0:2] + 12 );
    int comparedMin = String.valueOf(comparedTime[3:5]);
    int comparedT = comparedHour*60 + comparedMin;

    //obviously currentTime is alredy the correct format; just need to convert to minutes
    int currentHour = String.valueOf(currentTime[0:2]);
    int currentMin = String.valueOf(currentTime[3:5]);
    int currentT = currentHour*60 + currentMin;

    return (currentT > comparedT);
}

这有点麻烦，必须弄混弦乐之类的东西，但是有可能。您还必须注意零填充compareTime或只是在函数中进行检查

获取当前时间并检查时间是否已过一定时间

2 个答案: