我有两个功能。
我在trendyolStocksUpdate()
函数内部使用循环多次调用syncTrendyolOFFStocks()
函数。
我使用了async/await
,但没有依次调用trendyolStocksUpdate()
函数。它同时运行。
我的代码有什么问题?
以下是两个功能:
async function syncTrendyolOFFStocks(){
//This function sends "out of stock products" one by one
//to trendyolStocksUpdate function, so they their quantity will be initalized to 0
//For example, T-Shirt XL Yellow, and T-Shirt XXL Red are sent.
for(var product in all){
var colors = all[product];
for(var singleColor in colors[0]){
var size = colors[0][singleColor];
for(var index in size){
var singleSize = size[index];
await trendyolStocksUpdate(0,"",allProducts[product],singleSize,singleColor,0);
}
}
}
}
async function trendyolStocksUpdate(stockCount,price,product,size,color,rowCount){
//This function sends given Product Variation to trendyolUpdateStock.php with jQuery.ajax
//recursively. 1000 product's quantity are equalized to 0, once at a time.
dataObj = {
rowCount: rowCount,
product: product,
size:size,
color:color,
stockCount: stockCount,
};
if(price != ""){
dataObj["price"] = price;
}
await jQuery.ajax({
type: "POST",
url: "/wp-content/plugins/promc/templates/trendyolUpdateStock.php",
dataType: 'json',
data: dataObj,
success: function(data)
{
if(data.numberOfRows == 1000)
{
rowCount = rowCount + 1000;
trendyolStocksUpdate(stockCount,price,product,size,color,rowCount);
}
else
{
jQuery("#trendyolMonitor").append("<h3>Completed!</h3>");
rowCount = 0;
}
},
error: function(XMLHttpRequest, textStatus, errorThrown)
{
}
});
}
答案 0 :(得分:1)
当您在成功函数中调用trendyolStocksUpdate(stockCount,price,product,size,color,rowCount);
时,不会等待它。因此该函数将在递归调用完成之前返回。
代替使用成功函数,您可以在等待的ajax调用之后放入该逻辑。
async function trendyolStocksUpdate(stockCount,price,product,size,color,rowCount){
//This function sends given Product Variation to trendyolUpdateStock.php with jQuery.ajax
//recursively. 1000 product's quantity are equalized to 0, once at a time.
dataObj = {
rowCount: rowCount,
product: product,
size:size,
color:color,
stockCount: stockCount,
};
if(price != ""){
dataObj["price"] = price;
}
try {
const data = await jQuery.ajax({
type: "POST",
url: "/wp-content/plugins/promc/templates/trendyolUpdateStock.php",
dataType: 'json',
data: dataObj
});
if(data.numberOfRows == 1000)
{
rowCount = rowCount + 1000;
await trendyolStocksUpdate(stockCount,price,product,size,color,rowCount);
}
else
{
jQuery("#trendyolMonitor").append("<h3>Completed!</h3>");
rowCount = 0;
}
} catch (error) {
// Error stuff…
}
}
答案 1 :(得分:-1)
您的trendyolStocksUpdate
函数需要返回一个Promise才能正常工作。
答案 2 :(得分:-1)
即使您已经等待 jQuery Ajax仍然是异步的并且具有自己的回调函数。尝试在jQuery Ajax选项中将async设置为false。
async: false
不建议这样做,因为它会破坏Ajax的全部目的。但是您的问题似乎更多是针对同步api调用,因此这可能为您解决了问题。