Question

当我使用电池电源或交流电源时，我正在使用psutil和Python通知我。我有一个while循环，可以连续检查电池电量。我希望它在使用电池供电时通知我，但只能通知一次。如果我在任何地方声明变量power_notification = 0，则它将在while循环再次运行时将其重置为0。我该如何保存计数，这样它才通知我一次，直到我们重新使用AC为止？我没有收到任何错误，但它不断打印，表明我们使用电池供电。

import psutil

power_good = True

def check_power_status():
    power_notification = 0
    battery = psutil.sensors_battery()
    plugged_in = battery.power_plugged
    percent = str(battery.percent)

    if not plugged_in:
        if power_notification == 0:
            plugged_in = "We are on battery power."
            print(plugged_in + "\n" + "You have " + percent + "% of your battery remaining.")
            power_notification = 1
        else:
            power_good = False
            return power_good
    else:
        power_good = True
        return power_good

while power_good:
    check_power_status()

Answer 1

我相信您唯一需要做的就是全局设置 power_notification ，并在电源良好时将其重置为0：

import psutil

power_good = True
power_notification = 0

def check_power_status():
    battery = psutil.sensors_battery()
    plugged_in = battery.power_plugged
    percent = str(battery.percent)

    if not plugged_in:
        if power_notification == 0:
            plugged_in = "We are on battery power."
            print(plugged_in + "\n" + "You have " + percent + "% of your battery remaining.")
            power_notification = 1
        else:
            power_good = False
            return power_good
    else:
        power_good = True
        power_notification = 0
        return power_good

while power_good:
    check_power_status()

这能回答您的问题吗？

Answer 2

您需要保持它以new_col_headers, *new_col_bodies = new_cols.transpose #=> [["age", "iq"], [22, 85], [110, 140]] new_col_headers #=> ["age", "iq"] new_col_bodies #=> [[22, 85], [110, 140]] new_col_bodies = new_col_bodies.transpose #=> [[22, 110], [85, 140]]的身份运行，因此daemon应该一直都while。因此，我看不出使用True的任何理由。

power_good应该在函数之外，以保持其值。

power_notification

如何在If语句中执行通知，但在Python中继续执行While循环？

2 个答案: