使用label.new在行上方对齐文本

Question

我正在尝试将一行中的文本对齐，以使标签中的第一个字母与该行的左边缘完全对齐，而不考虑我们正在查看的时间范围。 Here is a link to the image showing how it currently appears。

代码如下：

draw_adr_hilo(hi_level, lo_level, res, adr, level_color) =>
var line hi_line = na
var line lo_line = na
if new_bar(res)
    line.set_x2(hi_line, bar_index)
    line.set_x2(lo_line, bar_index)
    line.set_extend(hi_line, extend.none)
    line.set_extend(lo_line, extend.none)
    hi_line := line.new(bar_index, hi_level, bar_index, hi_level, extend=extend.right, color=level_color)
    lo_line := line.new(bar_index, lo_level, bar_index, lo_level, extend=extend.right, color=level_color)
    label.new(bar_index, hi_level, "Average Range: " + tostring(to_pips(adr),'#.##') + " pips", xloc.bar_index, yloc.price, style=label.style_none, textcolor=color.white)
if not na(hi_line) and line.get_x2(hi_line) != bar_index
    line.set_x2(hi_line, bar_index)
    line.set_x2(lo_line, bar_index)

我尝试将“ bar_index”从0手动更改为另一个数字，但是标签中的文本继续向左移动，远离行。

我还有一个问题。我想在这行上方有两行文字。例如，我目前有一个标签称为“平均范围”，您能否提供在当前标签上方或下方添加另一个标签所需的指导？因此它将是“平均范围”，hi_line的价格高于或低于该价格。

非常感谢，谢谢您的帮助！

Answer 1

精确的水平对齐将存在问题，因为文本在标签中居中。在这里看起来不错，但在所有图表TF上都不是完美的。请参见此代码中的lbl3。

对于上面的多余行，上面的答案将起作用。有关该行上方和下方的行，请参见代码中的lbl1和lbl2：

//@version=4
study("Labels on Lines", "", true)
yp = highest(20)
newYp = change(yp)
if newYp
    // Labels up and down are used to print above and below line, with invisible color so we don't see them.
    lbl1 = label.new(bar_index, yp, "Above1\nAbove2", color=#00000000, style=label.style_labeldown, textcolor=color.green)
    lbl2 = label.new(bar_index, yp, "Below1\nBelow2", color=#00000000, style=label.style_labelup, textcolor=color.red)
    // Label none is used here because aligns vertically above line.
    // Left padding of text with spaces must vary with length of string since text is centered.
    // Horizontal alignment won't always be perfect.
    lbl3 = label.new(bar_index, yp, "            On Line", style=label.style_none, size=size.large, textcolor=color.orange, xloc=xloc.bar_index)
    if newYp[1]
        // Delete previous label when there is a consecutive new high, as there's no line plot in that case.
        label.delete(lbl1[1])
        label.delete(lbl2[1])
        label.delete(lbl3[1])
plot(newYp ? na : yp, "", color.gray, 2, plot.style_linebr, offset = -1)