Question

import random
import os
import json

class User:
    def _init_(self, username, password, balance):
        self.username = username
        self.password = password
        self.balance = balance



def file_read(source):
    with open (source) as file:
        data = file.read()
        dictionary = json.loads(data)
        return dictionary

然后外部文件是这个

{"John":["pass123", 2000], "Jenson": ["pass123", 2000]}

我最初的想法是使用 for items in dict 但是我不确定如何从最好由用户名命名的对象中创建多个对象谢谢。

Answer 1

可能是您要找的东西。请记住，它是__init__而不是_init_。

import json

def file_read(source):
    with open(source) as file:
        data = file.read()
        dictionary = json.loads(data)
        return dictionary

class User:
    def __init__(self, username, password, balance):
        self.username = username
        self.password = password
        self.balance = balance

    def __str__(self): # String representation of the object for the output.
        return f"{self.username}@{self.password} with balance of {self.balance}"

dictionary = file_read("file.json")

users = []
for key, item in dictionary.items():
    user = User(key, item[0], item[1])
    users.append(user)

# Printing results for output sake.
for user in users:
    print(user)

输出：

John@pass123 with balance of 2000
Jenson@pass123 with balance of 2000

file.json为：

{"John":["pass123", 2000], "Jenson": ["pass123", 2000]}

Answer 2

使用dict理解和var-args的简单解决方案：

{ k: User(k, *v) for k, v in file_read(filename).items() }

或者，您也可以通过销毁来做到这一点：

{ k: User(k, pw, bal) for k, (pw, bal) in file_read(filename).items() }

Answer 3

我想您要问的是为文件中的每个名称创建对象。

class User:
    def __init__(self, username, password, balance):
        self.username = username
        self.password = password
        self.balance = balance
def file_read(source):
    with open (source) as file:
       data = file.read()
       dictionary = json.loads(data)
       return dictionary
dicValuesRead = file_read(source)
d = {}
for k,v in dicValuesRead.items():
    d[k] = User(k, v[0], v[1])

print (d)

Answer 4

最好以用户名命名

这是有问题的，针对您的问题的最常见解决方案是创建{username:object}对字典。参见How do I create a variable number of variables?

您的函数返回一个字典。

在dictionary items上迭代，将产生(name,(password,balance))个元组
为每个项目提取单独的值； name,(password,balance)= item
将它们传递给类以创建一个新对象并将其添加到字典中
new_dict[name] = object

遍历字典并为每个键创建一个对象，其键值在同一对象内

4 个答案: