为什么需要为此自定义钩子将settimeout包装在useEffect钩子中?
function useWait (delay) {
const [show, setShow] = React.useState(false)
React.useEffect(() => {
const id = window.setTimeout(() => {
setShow(true)
}, delay)
return () => window.clearTimeout(id)
}, [delay])
return show
}
答案 0 :(得分:1)
如果不将setTimeout或setInterval放入useEffect中,则每次重新发布组件时,它将重新初始化并且不会清除。
看下面的例子。每次您通过按按钮增加计数器时,父组件都会重新渲染,这会滴答所有孩子(包括我的setTimeout组件)。多次按下按钮,您将看到组件重新渲染几次,然后您将看到“超时完成”多次。
然后在下面我添加了一个带有useEffect的代码段,您将看到超时仅运行一次。
这能回答您的问题吗?
编辑:以下是一个代码框,可以尝试https://codesandbox.io/s/boring-liskov-4kjgm?fontsize=14&hidenavigation=1&theme=dark
无使用效果
import React, {useState} from "react";
import ReactDOM from "react-dom";
import "./styles.css";
function App() {
const [counter, increment] = useState(0);
const doIncrement = () => increment(counter + 1);
return (
<div className="App">
<Counter counter={counter} increment={doIncrement} />
<OtherComponent />
</div>
);
}
const Counter = ({counter, increment}) => {
return <button onClick={()=>increment()}>{counter}</button>
}
const OtherComponent = () => {
console.log('I rerendered');
const timeout = setTimeout(() => console.log('timeout finished'), 1000)
return <h1> Hello world </h1>
}
const rootElement = document.getElementById("root");
ReactDOM.render(<App />, rootElement);
具有useEffect
import React, {useState, useEffect} from "react";
import ReactDOM from "react-dom";
import "./styles.css";
function App() {
const [counter, increment] = useState(0);
const doIncrement = () => increment(counter + 1);
return (
<div className="App">
<Counter counter={counter} increment={doIncrement} />
<OtherComponent />
</div>
);
}
const Counter = ({counter, increment}) => {
return <button onClick={()=>increment()}>{counter}</button>
}
const OtherComponent = () => {
console.log('I rerendered');
useEffect(() => {
const timeout = setTimeout(() => console.log('timeout finished'), 1000)
return () => clearTimeout(timeout)
}, [])
return <h1> Hello world </h1>
}
const rootElement = document.getElementById("root");
ReactDOM.render(<App />, rootElement);