UIMenuController在iOS 13.2中不可见

Question

我有一个长按处理程序，显示UIMenuController，它在

private func longPressHandler(sender: UILongPressGestureRecognizer) {
    guard
        sender.state == .began,
        let senderView = sender.view,
        let superView = sender.view?.superview
    else {
        return
    }

    senderView.becomeFirstResponder()

    UIMenuController.shared.setTargetRect(senderView.frame, in: superView)
    UIMenuController.shared.setMenuVisible(true, animated: true)
}

private func makeMenuController() {
    UIMenuController.shared.menuItems = [
        UIMenuItem(title: "ui.report".localized, action: ChatCustomMenuItems.report),
        UIMenuItem(title: "ui.chat.reply".localized, action: ChatCustomMenuItems.reply),
        UIMenuItem(title: "ui.action.block".localized, action: ChatCustomMenuItems.block)
    ]
}

在文档中，我发现setTargetRect和setMenuVisible已弃用

像这样进行更改仍然没有帮助。有解决办法吗？

if #available(iOS 13.0, *) {
    UIMenuController.shared.isMenuVisible = true
    UIMenuController.shared.showMenu(from: superView, rect: senderView.frame)
} else {
    UIMenuController.shared.setTargetRect(senderView.frame, in: superView)
    UIMenuController.shared.setMenuVisible(true, animated: true)
}

Answer 1

我遇到了完全相同的问题！该问题可能是由于未致电

引起的

window?.makeKeyAndVisible()

或在application:didFinishLaunchingWithOptions:方法之前调用它

Answer 2

只需确保您没有在代码中创建UIMenuController的其他实例，例如 let menu = UIMenuController（）

Answer 3

就我而言，我需要致电becomeFirstResponder来显示菜单：

window?.makeKey()
becomeFirstResponder()