Question

**该代码的目的是从文件中读取一些数据。数据分为几行，每行的数据都使用“-”字符进行拆分。该代码应将数据拆分为单独的字符串，并将单独的字符串传输到称为“ splitLine”的数组中。测试数据的重点是在其中抛出“ ArrayIndexOutOfBoundsException”。但是，在给出此异常之后，catch应当只允许代码继续运行，但是不起作用。 **

public class asd 

{

    public static void main(String[] args)
    {
        String line = "";
        String[] splitLine;
        Scanner keyboard = new Scanner (System.in);
        System.out.print("Enter the file name: ");
        String filename = keyboard.nextLine();

        Scanner fileReader = null;

        try
        {
            File Fileobject = new File (filename);
            fileReader = new Scanner (Fileobject);
            System.out.println("The file " + filename + " contains the following lines");
            System.out.println("==============================");
            int x=0;




            while(fileReader.hasNext())
            { 
                try 
                {
                    line = fileReader.nextLine();
                    splitLine = line.split(" - "); //For assignment use line.split(" - ")
                    System.out.printf("Title: %20s \nAuthor: %17s \nPublisher: %9s\nPrice: %10s\nPages: %8s\nISBN: %16s\n===================\n", splitLine[x] , splitLine[x+1], splitLine[x+2], splitLine[x+3], splitLine[x+4], splitLine[x+5]);
                } 
                catch (ArrayIndexOutOfBoundsException  e) 
                {
                    continue;
                }





        }
    }
        catch(FileNotFoundException e)
            {
                System.out.println("Error - file does not exist");
                System.exit(0);
            } 

    }
}

Answer 1

我建议在访问输入之前先对输入进行验证，而不仅仅是使用它并导致异常失败。

另一个方向：

无论如何-根据您的消息，您的数据以“-”组织，那么为什么不只将相同的数据保存为JSON文件呢？

然后您可以像这样将其读取到您的对象中：首先，创建自己的 Article.java 类然后，编写如下代码：

import com.fasterxml.jackson.*

    public static void someMethod()
    {
        File file = new File("....somepath...\\Desktop\\data.json");
        ObjectMapper mapper = new ObjectMapper();
        Article article = mapper.readValue(file , Article.class);

        System.out.printf("Title: %20s \nAuthor: %17s \nPublisher: %9s\nPrice: %10s\nPages: %8s\nISBN: %16s\n===================\n", article.getTitle(), article.getPublisher(), article.getPrice(), article.getPages(), article.getSomethingMore1(), article.getSomethingMore2());

    }

Answer 2

据我所知，当splitLine不包含必需值时，您想跳过迭代吗？在那种情况下，仅仅检查您是否有足够的参数会不会更简单？

 splitLine = line.split(" - "); //For assignment use line.split(" - ")
 if(splitLine.lenght != 6) {
  continue;
 }
 System.out.printf("Title: %20s \nAuthor: %17s \nPublisher: %9s\nPrice: %10s\nPages: %8s\nISBN: %16s\n===================\n", splitLine[x] , splitLine[x+1], splitLine[x+2], splitLine[x+3], splitLine[x+4], splitLine[x+5]);

此外，我建议将内部try提取为单独的方法，以提高可读性

try and catch语句没有给我任何结果？

2 个答案: