我已经使用单词互操作打开了一个单词文档,并添加了几段文字。它们的长度取决于一系列因素。然后,我在这样的下标中添加一行包含CR的文本(Unicode中不包含字母CR的下标):
Dim word As Word.Application = New Word.Application()
Dim doc As Word.Document
'more code inserting paragraphs here
Dim Paratext as string
Paratext = "Elastic Critical Buckling Load N_CR=(π² (E/Yₘ )I)/(L_CR∙L² )"
para0 = doc.Content.Paragraphs.Add
para0.Range.Text = Paratext
para0.Range.InsertParagraphAfter()
para0.Range.Style = doc.Styles("Normal")
Dim Rstart As Int16 = Paratext.IndexOf("CR")
Dim Rend As Int16 = Paratext.IndexOf("=")
' this is wrong: I select the range in the document
' using the location in the paragraph.
Dim SRange = doc.Range(Rstart, Rend)
SRange.Select()
Dim currentselection As Word.Selection = word.Selection
currentselection.Font.Subscript = 1
编辑:我选择了错误的文本。我要在刚添加的段落中标识CR字母的位置,并将其应用于已经添加了几个段落的文档中。因此,文档索引35和36的两个字符而不是段落变为下标。 如何获取刚刚添加的段落开头的索引?
答案 0 :(得分:0)
已解决:
Dim word As Word.Application = New Word.Application()
Dim doc As Word.Document
'more code inserting paragraphs here
'locate the end of the document so far
Dim DocEnd As Int16 = doc.Content.End - 1
Dim Paratext as string
Paratext = "Elastic Critical Buckling Load N_CR=(π² (E/Yₘ )I)/(L_CR∙L² )"
para0 = doc.Content.Paragraphs.Add
para0.Range.Text = Paratext
para0.Range.InsertParagraphAfter()
para0.Range.Style = doc.Styles("Normal")
Dim Rstart As Int16 = Paratext.IndexOf("CR")
Dim Rend As Int16 = Paratext.IndexOf("=")
Dim SRange = doc.Range(Rstart + DocEnd, Rend + DocEnd)
SRange.Select()
Dim currentselection As Word.Selection = word.Selection
currentselection.Font.Subscript = 1