Question

我正在尝试使用dplyr软件包中的filter函数从符合条件的数据框中提取行。

我的数据框如下：

head(EIA)
  length location  stype  rock  dist  ftype  depth aspect  degree  drain  TWI
1   len1     loc3 stype2 rock3 dist3 ftype1 depth2   asp2 degree2 drain4 TWI1
2   len4     loc2 stype2 rock3 dist1 ftype4 depth3   asp4 degree3 drain4 TWI3
3   len2     loc2 stype2 rock2 dist1 ftype4 depth3   asp1 degree2 drain4 TWI2
4   len4     loc2 stype2 rock3 dist2 ftype4 depth3   asp4 degree2 drain4 TWI2
5   len4     loc2 stype1 rock3 dist1 ftype2 depth3   asp1 degree3 drain4 TWI2
6   len4     loc3 stype2 rock2 dist1 ftype2 depth3   asp4 degree3 drain1 TWI2

，依此类推。总行数：10560

但是由于我试图在for循环中完成此工作，因此过滤器函数中的每个元素都必须与变量（colcol，aa，bb，cc）一起传递：

 colcol
    [1] "length"   "location" "stype"    
 aa;bb;cc
    [1] "len1"
    [1] "loc2"
    [1] "stype1"

我试图做这样的过滤功能，但是没有用：

filter(EIA, colcol[1] == aa & colcol[2] == bb & colcol[3] == cc)

结果必须提取两行。我认为这是由于colcol [1]元素周围的双引号引起的。我尝试使用as.symbol，as.name和noquote函数删除这些引号，但是它们不起作用。

这个问题有解决方案吗？

谢谢。

Answer 1

子集是此类问题的最佳解决方案

 aa <- subset(EIA,EIA$lenght=='len1')

以上可能是您喜欢的示例以及简单而智能的解决方案。您还可以使用和（＆）条件提取行。

 aa <- subset(EIA,EIA$lenght=='len1' & EIA$location=='loc2')

Answer 2

将其转换为符号，然后求值

library(dplyr)
filter(EIA,!!sym(colcol[1]) == aa & !!sym(colcol[2]) == bb & !!sym(colcol[3]) == cc)

例如，当我们评估第一个条件时，我们得到

filter(EIA, !!sym(colcol[1]) == aa)
#  length location  stype  rock  dist  ftype  depth aspect  degree  drain  TWI
#1   len1     loc3 stype2 rock3 dist3 ftype1 depth2   asp2 degree2 drain4 TWI1

数据

EIA <- structure(list(length = structure(c(1L, 3L, 2L, 3L, 3L, 3L), 
.Label = c("len1", "len2", "len4"), class = "factor"), location = structure(c(2L, 
1L, 1L, 1L, 1L, 2L), .Label = c("loc2", "loc3"), class = "factor"), 
stype = structure(c(2L, 2L, 2L, 2L, 1L, 2L), .Label = c("stype1", 
"stype2"), class = "factor"), rock = structure(c(2L, 2L, 
1L, 2L, 2L, 1L), .Label = c("rock2", "rock3"), class = "factor"), 
dist = structure(c(3L, 1L, 1L, 2L, 1L, 1L), .Label = c("dist1", 
"dist2", "dist3"), class = "factor"), ftype = structure(c(1L, 
3L, 3L, 3L, 2L, 2L), .Label = c("ftype1", "ftype2", "ftype4"
), class = "factor"), depth = structure(c(1L, 2L, 2L, 2L, 
2L, 2L), .Label = c("depth2", "depth3"), class = "factor"), 
aspect = structure(c(2L, 3L, 1L, 3L, 1L, 3L), .Label = c("asp1", 
"asp2", "asp4"), class = "factor"), degree = structure(c(1L, 
2L, 1L, 1L, 2L, 2L), .Label = c("degree2", "degree3"), class = "factor"), 
drain = structure(c(2L, 2L, 2L, 2L, 2L, 1L), .Label = c("drain1", 
"drain4"), class = "factor"), TWI = structure(c(1L, 3L, 2L, 
2L, 2L, 2L), .Label = c("TWI1", "TWI2", "TWI3"), class = "factor")), 
class = "data.frame", row.names = c("1", "2", "3", "4", "5", "6"))

colcol <- c("length",   "location", "dist")
aa <- "len1"
bb <- "loc2"
cc <- "stype1"

使用colnames（）循环filter（）函数后如何删除双引号

2 个答案: