Question

var arr = [[],[],null,[[],[]],[[[]]]];
$( document ).ready(function() {
  
  
  
  addChild(arr, 'main');
  
  
  
});

function inscribe(numbers, value) {
    while(numbers.length>1){
      arr = arr[numbers.shift()];
    }

    arr[numbers.shift()] = value;
    
    addChild(arr, 'main');
    
  }
  
  function addChild(subarr, id) {
    var el = document.getElementById(id);
    var ul = document.createElement("ul");
    el.appendChild(ul);
    subarr.forEach(function(item, index){
      var node = document.createElement("div");
      var textnode = document.createTextNode(id + '-' + index);
      node.appendChild(textnode);
      node.id = id + '-' + index;
      ul.appendChild(node);
      if(item && item.length)
        addChild(item, node.id);
    })
  }

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="main"> </div>

<button onclick="inscribe([3,1], [[]])">inscribe([3,1], [[]])</button>

让我们假设我有一个nD数组，其值是动态变化的。 let arr = [[],[],[[],[]],null,[]];。我需要一个接收数字数组和一个值的函数来更改主数组的值。

/*
 * numbers: an array of integers which indicates which element of array should be set
 * value: the value that should be set
 */
inscribe(numbers, value) {
   // set value for desired position
}

例如，如果数字为[x,y,z]，则应更改arr[x][y][z] = value。请注意，我们不知道numbers数组的长度。对实现该功能有何建议？

Answer 1

您可以使用递归来获取/更改值；

func applicationWillTerminate(_ application: UIApplication) {
     bgTask = application.beginBackgroundTask(withName:"Flink_logOut", expirationHandler: {() -> Void in
         // Do something to stop our background task or the app will be killed
     }
     // Called when the application is about to terminate. Save data if appropriate. See also applicationDidEnterBackground:.
}

更改多维数组JavaScript的值

1 个答案: