Question

我正在尝试仅查询此复杂字符串内K列中数字> 0的数据。

=QUERY('Form Responses 1'!A1:K,"SELECT *" & if(COUNTBLANK('Helper Formulas'!A1:A3)=3,""," WHERE " & TEXTJOIN(" AND ",TRUE,'Helper Formulas'!A1:A3)),1)

我尝试过...

=QUERY('Form Responses 1'!A1:K,"SELECT * WHERE K > 0" & if(COUNTBLANK('Helper Formulas'!A1:A3)=3,""," WHERE " & TEXTJOIN(" AND ",TRUE,'Helper Formulas'!A1:A3)),1)

但是要不断出错。

不确定我需要做什么。

Answer 1

第二个公式有两个WHERE。用AND替换第二个，例如：

=QUERY('Form Responses 1'!A1:K,"SELECT * WHERE K > 0" & if(COUNTBLANK('Helper Formulas'!A1:A3)=3,""," AND " & TEXTJOIN(" AND ",TRUE,'Helper Formulas'!A1:A3)),1)

如果最终出现太多“ AND”，则可能需要进行调整。

解决此类问题时，仅在单元格中显示字符串（即，query()函数内部的位）通常会很有帮助。那将很快显示出错误。

Answer 2

尝试：

=QUERY('Form Responses 1'!A1:K, 
 "where K > 0"&IF(COUNTBLANK('Helper Formulas'!A1:A3)=3,,
 " and "&TEXTJOIN(" and ", 1, 'Helper Formulas'!A1:A3)), 1)

如何将WHERE函数添加到复杂的字符串

2 个答案: