我正在尝试仅查询此复杂字符串内K列中数字> 0的数据。
=QUERY('Form Responses 1'!A1:K,"SELECT *" & if(COUNTBLANK('Helper Formulas'!A1:A3)=3,""," WHERE " & TEXTJOIN(" AND ",TRUE,'Helper Formulas'!A1:A3)),1)
我尝试过...
=QUERY('Form Responses 1'!A1:K,"SELECT * WHERE K > 0" & if(COUNTBLANK('Helper Formulas'!A1:A3)=3,""," WHERE " & TEXTJOIN(" AND ",TRUE,'Helper Formulas'!A1:A3)),1)
但是要不断出错。
不确定我需要做什么。
答案 0 :(得分:0)
第二个公式有两个WHERE
。用AND
替换第二个,例如:
=QUERY('Form Responses 1'!A1:K,"SELECT * WHERE K > 0" & if(COUNTBLANK('Helper Formulas'!A1:A3)=3,""," AND " & TEXTJOIN(" AND ",TRUE,'Helper Formulas'!A1:A3)),1)
如果最终出现太多“ AND”,则可能需要进行调整。
解决此类问题时,仅在单元格中显示字符串(即,query()
函数内部的位)通常会很有帮助。那将很快显示出错误。
答案 1 :(得分:0)
尝试:
=QUERY('Form Responses 1'!A1:K,
"where K > 0"&IF(COUNTBLANK('Helper Formulas'!A1:A3)=3,,
" and "&TEXTJOIN(" and ", 1, 'Helper Formulas'!A1:A3)), 1)