我最近(通过一些帮助)将这个简单的表单写入电子邮件脚本。它的工作原理,唯一的问题是它在运行时重定向到包含的php脚本。有没有人对如何阻止这种情况发生任何想法,而只是在原始页面上显示感谢信?
的index.php
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Megaform</title>
</head>
<body>
<?php include 'form.php' ?>
</body>
</html>
form.php的
<form name="email" method="post" action="email.php">
<p>
<label for="name">Full Name</label>
<input type="text" name="name" id="name">
</p>
<p>
<label for="email">Email Address</label>
<input type="text" name="email" id="email">
</p>
<p>
<label for="phone">Phone Number</label>
<input type="text" name="phone" id="phone">
</p>
<p>
<label for="subject">Subject</label>
<input type="text" name="subject" id="subject">
</p>
<p>
<label for="message">Message<br>
</label>
<textarea name="message" id="message" cols="45" rows="5"></textarea>
</p>
<p><input type="submit" name="send" id="send" value="Submit"><input type="reset" name="send" id="send" value="Reset">
</p>
</form>
email.php
<?php
// Get the Variables
$name = $_POST['name'];
$visitor_email = $_POST['email'];
$phone = $_POST['phone'];
$subject = $_POST['subject'];
$message = $_POST['message'];
// Validate against spammers
function IsInjected($str)
{
$injections = array('(\n+)',
'(\r+)',
'(\t+)',
'(%0A+)',
'(%0D+)',
'(%08+)',
'(%09+)'
);
$inject = join('|', $injections);
$inject = "/$inject/i";
if(preg_match($inject,$str))
{
return true;
}
else
{
return false;
}
}
if(IsInjected($visitor_email))
{
echo "Bad email value!";
exit;
}
// Compose the Email
$email_from = 'a@b.com'; // Set a valid email address that the form can use
$email_subject = "New Form submission - $subject"; // Change the message subject here
$email_body = "You have received a new message from $name ($phone) .\n Here is the message:\n $message";
// Send The Email
$to = "c@d.com"; // Set a valid email address to send the form to
$headers = "From: $email_from \r\n";
$headers .= "Reply-To: $visitor_email \r\n";
mail($to,$email_subject,$email_body,$headers);
?>
<p>Thankyou for your email.</p>
答案 0 :(得分:2)
将您的表单标记更改为:
<form name="email" method="post" action="index.php">
并将您的索引更改为:
<body>
<?php
if (isset($_POST['email'])) {
include 'email.php';
} else {
include 'form.php';
}
?>
</body>
因此,如果表单已提交,请发送电子邮件,否则,请显示表单。
答案 1 :(得分:1)
您需要将表单目标设置为文件itselfe。
<form name="email" method="post" action="form.php">
并在那里包含来自email.php的代码。
if ($_POST['email']) {
... code from email.php ...
... and success message ...
}
只有在发送表格(并设置了电子邮件)后才会执行此部分。
答案 2 :(得分:1)
您可以直接从form.php
重定向将它放在form.php
的末尾header("url: index.php");
甚至:
header("url: index.php?sent=true");
在index.php中你可以拥有
if($_GET['sent']){
echo "Message Sent.";
}