JTextField textField = (JTextField) evt.getSource();
textField.setBorder( /* whatever border you need */ );
这是我的输出
#include <iostream>
#include <string>
#include <ctime>
using namespace std;
class PVR {
private:
int channel;
public:
PVR() {
cout << "Select the channel ==> ";
cin >> channel;
cout << endl;
}
};
class DVR {
private:
string position;
public:
DVR() {
cout << "Select the position ==> ";
cin >> position;
cout << endl;
}
};
class Oven {
private:
string food;
public:
Oven() {
cout << "What do you want to bake? ==> ";
cin >> food;
cout << endl;
}
};
class PrgDevice {
private:
tm startTime;
tm stopTime;
int choice;
int choice1;
char c;
public:
void dateTime() {
cout << "Enter start date and start time: ";
cin >> startTime.tm_mday >> startTime.tm_mon >> startTime.tm_year >> startTime.tm_hour >> startTime.tm_min >> startTime.tm_sec;
cout << "Enter stop date and stop time: ";
cin >> stopTime.tm_mday >> stopTime.tm_mon >> stopTime.tm_year >> stopTime.tm_hour >> stopTime.tm_min >> stopTime.tm_sec;
}
void mainMenu() {
while (choice != 3) {
cout << "Main menu options: \n";
cout << " 1. Select a device to program (contains a submenu)" << endl;
cout << " 2. Display current status of all devices" << endl;
cout << " 3. Exit" << endl;
cout << "Enter your option => ";
cin >> choice;
if (choice == 1) {
subMenu();
}
else if (choice == 2) {
cout << choice;
}
else {
}
}
}
void subMenu() {
do {
cout << "Select a device:" << endl;
cout << " 1. PVR" << endl;
cout << " 2. Camera DVR" << endl;
cout << " 3. Oven" << endl;
cout << "Enter your option => ";
cin >> choice1;
if (choice1 == 1) {
PVR n1;
}
else if (choice1 == 2) {
DVR n2;
}
else {
Oven n3;
}
dateTime();
cout << endl;
cout << "Another device to program Y/N ? => ";
cin >> c;
}
while(c == 'Y' || c == 'y');
}
};
int main() {
PrgDevice obj1;
obj1.mainMenu();
system("pause");
return 0;
}
当我按Enter键时,我的程序进入了一个循环,我不知道为什么这么做
答案 0 :(得分:4)
问题是您的程序希望用户输入时间和日期作为空格分隔的值,而您将它们输入为冒号分隔的值。
那是
cin >> startTime.tm_mday >> startTime.tm_mon >> ...
会将12
读入startTime.tm_mday
,但是输入中的:
与startTime.tm_mon
类型不匹配。这样将停止所有输入读取,将:
留在输入缓冲区中,供您进行下一个输入操作。
下一个输入操作用于stopTime
,由于输入缓冲区中的:
,该操作将立即失败。因此,您回到了subMenu
函数中,冒号将被读入c
中。并且':'
不等于'Y'
或'y'
,因此循环结束,subMenu
函数返回到mainMenu
,在此您再次打印菜单。
答案 1 :(得分:3)
对我来说,这似乎并不是一个无限循环。尝试输入开始时间为:
12 1 19 20 0 0
cin不会神奇地处理输入中的':'字符,因此您可能需要阅读整行,并解析出':'字符。