Question

我正在用Python和Tweepy制作一个机器人，该机器人在被提及时会给出图像答复，但是他一直在回复相同的推文。我试图使用If来解决这个问题，但是没有用。

import tweepy
import os
import time
import random

os.chdir ('images')

#Keys to API

consumer_key = ''
consumer_secret = ''
access_token = ''
access_token_secret =''

#Auth to API
auth = tweepy.OAuthHandler(consumer_key, consumer_secret)    
auth.set_access_token(access_token, access_token_secret)
api = tweepy.API(auth)

user = api.me()
print (user.name)

def reply_bot():
    search = api.search(q='@KancolleSleep')
    for tweet in search:
        print (f'UserName: {tweet.user.screen_name}')
        name = tweet.user.screen_name
        message = []
        message += (tweet.text)
        message2 = (tweet.text)
        if message2 != message:
            print (f'Tweet: {tweet.text}')
            media_ids = []
            image1 = random.choice(os.listdir('.'))
            file = api.media_upload(image1)
            media_ids.append(file.media_id)
            print (image1)
            text = (f'@{name}')
            api.update_status(status=text, media_ids=media_ids, in_reply_to_status_id=tweet.id)
        else:
            print ("Tweet already answered")

while True:
    reply_bot()
    time.sleep(15)

有一种有效的方法来防止这种情况发生吗？

Answer 1

我假设每条推文都有一个ID。您可以只存储漫游器已回复的推文ID的列表，并针对每条新推文检查它是否已在列表中。

这里是一个示例：

already_answered = []
def reply_bot():
    search = api.search(q='@KancolleSleep')
    for tweet in search:
        # add your code
        if tweet.id not in already_answered:
            # add your code
            already_answered.append(tweet.id)
        else:
            print('tweet already answered')

防止Tweepy脚本回复相同的提及

1 个答案: