有谁知道如何手动创建EntityManagerFactory
?当我手动说我的意思是让它消耗一个特殊的persistence.xml
文件?我所尝试的一切都让我失望。
Configuration configuration = new Configuration();
InputStream is = JPAUtil.class.getResourceAsStream("/s-persistence.xml");
configuration.addInputStream(is);
_entityManagerFactory = Persistence.createEntityManagerFactory(
puType.persistenceName, configuration.getProperties());
s-persistence.xml
看起来像:
<?xml version="1.0"?>
<persistence version="1.0" xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence
http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd">
<persistence-unit name="S_DATABASE" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<properties>
<property value="false" name="hibernate.show_sql"/>
<property value="org.hibernate.dialect.OracleDialect" name="hibernate.dialect"/>
<property value="oracle.jdbc.driver.OracleDriver" name="hibernate.connection.driver_class "/>
<property value="jdbc:oracle:thin:@xxx.xxx.xxx.xxx:TEST" name="hibernate.connection.url"/>
<property value="TESTOWNER" name="hibernate.connection.username"/>
<property value="TEST" name="hibernate.connection.password"/>
<property value="2" name="hibernate.connection.isolation"/>
</properties>
</persistence-unit>
</persistence>
运行java代码时出现以下错误。
ERROR :: org.hibernate.util.XMLHelper|Error parsing XML: XML InputStream(2) Document is invalid: no grammar found.
ERROR :: org.hibernate.util.XMLHelper|Error parsing XML: XML InputStream(2) Document root element "persistence", must match DOCTYPE root "null".
org.hibernate.MappingException: invalid mapping
就像在persistence.xml
中寻找hibernate特定语法一样。我也尝试过EJB3Configuration。看起来我的XML格式正确,这让我不知道为什么会收到这个错误。
答案 0 :(得分:0)
我认为你遇到的问题是
http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd
可能无法访问,因此根据它验证XML文件是行不通的。
尽量不给出这样的架构位置:
<persistence xmlns="http://java.sun.com/xml/ns/persistence">