Question

我需要在项目中使用wsdl Web服务方法
Web服务地址为：https://sep.shaparak.ir/payments/initpayment.asmx?WSDL
我用jaxb2生成了初始代码，现在当我使用相应的方法调用webservice时，我给出了
错误：

org.springframework.ws.InvalidXmlException：无法解析XML。嵌套的异常是org.xml.sax.SAXParseException; lineNumber：1； columnNumber：406; XML文档结构必须在其中开始和结束同一实体。

这是我的网络服务调用方法：

ObjectFactory factory = new ObjectFactory();
requestToken requestToken = factory.createRequestToken();
requestToken.setTermID("123456");
requestToken.setTotalAmount(currentInvoice.getFinalPrice().longValueExact());
requestToken.setRedirectUrl("http://localhost/done");
requestToken.setResNum(currentInvoice.getInvoiceCode());
RequestTokenResponse r;
try {
r = (RequestTokenResponse) soapConnector
                    .callWebService("https://sep.shaparak.ir/payments/initpayment.asmx?WSDL", requestToken);
} catch (Exception e) {
    log.debug(e.getMessage());
}

这是我的配置文件：

@Configuration
public class SEPConfig {
    @Bean
    public Jaxb2Marshaller marshaller() {
        Jaxb2Marshaller marshaller = new Jaxb2Marshaller();
        // this is the package name specified in the <generatePackage> specified in
        // pom.xml
        marshaller.setPackagesToScan("com.sinansoft.golrizan.web.wsdl");
        return marshaller;
    }

    @Bean
    public SOAPConnector soapConnector(Jaxb2Marshaller marshaller) {
        SOAPConnector client = new SOAPConnector();
        client.setDefaultUri("https://sep.shaparak.ir/payments/initpayment.asmx?WSDL");
        client.setMarshaller(marshaller);
        client.setUnmarshaller(marshaller);
        return client;
    }
}

和连接器文件

import org.springframework.ws.client.core.support.WebServiceGatewaySupport;

public class SOAPConnector extends WebServiceGatewaySupport {

    public Object callWebService(String url, Object request){
        return getWebServiceTemplate().marshalSendAndReceive(url, request,webServiceMessage -> {
            String s="";
        });
    }
}

有人可以告诉我我的代码或WSDL有什么问题吗？

调用Web服务返回一个错误，指出错误的xml

0 个答案: