Question

我有两个列表，如下所示：

https://docs.google.com/gview?embedded=true&url=[doc address]

和

listOne = [
    {phone: "123", name: "Joey"},
    {phone: "456", name: "Erik"},
    {phone: "789", name: "Teddy"},
]

我将如何比较这两个列表，对于每个重复项（listTwo = [ {phone: "123", name: "Joey", accoundId: "ID_001"}, {phone: "456", name: "Erik", accoundId: "ID_006"}, {phone: "5553", name: "Sebastian", accoundId: "ID_010"}, ]和phone完全匹配），如果存在重复项，则将值name中与{{ 1}}在listThree

中找到

因此：

accountId

JavaScript，Python或Apex解决方案受到高度赞赏

Answer 1

list1 = [
    {"phone": "123", "name": "Joey"},
    {"phone": "456", "name": "Erik"},
    {"phone": "789", "name": "Teddy"},
]

list2 = [
    {"phone": "123", "name": "Joey", "accountid": "ID_001"},
    {"phone": "456", "name": "Erik", "accountid": "ID_006"},
    {"phone": "5553", "name": "Sebastian", "accountid": "ID_010"},
]

list3=[]
for i in list1:
    for j in list2:
        if i['name'] == j['name'] and i['phone']==j['phone']:
             list3.append(j)

print(list3)
[{'phone': '123', 'name': 'Joey', 'accountid': 'ID_001'}, {'phone': '456', 'name': 'Erik', 'accountid': 'ID_006'}]

Answer 2

var commonFound = []; 
for (var i = 0, len = listOne.length; i < len; i++) { 
        for (var j = 0, len2 = listTwo.length; j < len2; j++) { 
            if ((listOne[i].phone == listTwo[j].phone) && (listOne[i].name == listTwo[j].name)) {
                commonFound.push(listTwo[j])
            }
        }
    }
console.log(commonFound)

Answer 3

我们有两个属性需要检查，例如phone和name。基于此，我们可以过滤一个数组：

const result = listTwo.filter(f=> 
    listOne.some(s => s.phone == f.phone && s.name == f.name));

这是一个示例：

let listOne = [
    {phone: "123", name: "Joey"},
    {phone: "456", name: "Erik"},
    {phone: "789", name: "Teddy"},
];

let listTwo = [
    {phone: "123", name: "Joey", accoundId: "ID_001"},
    {phone: "456", name: "Erik", accoundId: "ID_006"},
    {phone: "5553", name: "Sebastian", accoundId: "ID_010"},
];

const result = listTwo.filter(f=> 
    listOne.some(s => s.phone == f.phone && s.name == f.name));

console.log(result);

检查对象列表与另一个对象列表中的重复值

3 个答案: