这是数组的初始化。我已经有了可以使用的get和set方法。我的问题是示例,我使用我的addStudent方法,然后输入了三个名称。只有我输入的第一个学生为真,否则为假
static ArrayList<Dynamic> users = new ArrayList<Dynamic>();
这是我的搜索方法
public static void searchStudent() {
String trash= in.nextLine();
System.out.println("Please Enter First Name");
String find = in.nextLine();
for (int i=0; i<users.size(); i++) {
if(find.equalsIgnoreCase(users.get(i).getfName())){
System.out.println("Student is Found");
System.out.println(users.get(i));
menu();
}
else {
System.out.println("Student Not found");
menu();
}
}
}//end of searchStudent
答案 0 :(得分:1)
仅当学生是ArrayList中的第一个元素时,当前代码才会显示“找到学生”。要使其在整个列表中进行搜索,请使循环中其他代码块中的代码失效。
public static void searchStudent() {
String trash= in.nextLine();
System.out.println("Please Enter First Name");
String find = in.nextLine();
for (int i=0; i<users.size(); i++) {
if(find.equalsIgnoreCase(users.get(i).getfName())){
System.out.println("Student is Found");
System.out.println(users.get(i));
menu();
}
}
System.out.println("Student Not found");
menu();
}//end of searchStudent
答案 1 :(得分:1)
public static void searchStudent() {
String trash= in.nextLine();
System.out.println("Please Enter First Name");
String find = in.nextLine();
boolean found = false;
for (int i=0; i<users.size(); i++) {
if(find.equals(users.get(i).getfName())){
System.out.println("Student is Found");
System.out.println(users.get(i));
found = true;
menu();
}
}
if(found == false){
System.out.println("Student Not found");
menu();
}
}