我有PHP代码,可以检查电子邮件是否已经存在。问题是即使它不存在,它也将始终打印“电子邮件已存在”。该数据库运行良好。
$b = mysqli_query($con ,"insert into form2 (Email, Password) values ('$email', '$pass')");
$sql = "SELECT `Email`FROM `form2` WHERE `Email`='".$email."'";
$res=mysqli_query($con,$sql);
if (mysqli_num_rows($res) > 0)
{
die("Email already exists");
}
else
{
if($resultSet){
$resultSet = mysqli_query($con,$b);
echo"Added successfully";}
else
die("Not added");
}