尝试从网络获取链接

Question

该代码仅获得1个URL列表，然后停止。它应该获得209项。为什么只打印一行？

def parse_link(self, response):

    # Extract the list of products 
    results = response.xpath('//li[@class="s-item   "]')



    # Extract info for each product
    for product in results:
        name = product.xpath('//*[@class="s-item__link"]').extract_first()[30:124]

    yield{
    "Name":name,
    }

Answer 1

缩进不正确（您需要在yield循环内移动for）

def parse_link(self, response):

    # Extract the list of products 
    results = response.xpath('//li[@class="s-item   "]')



    # Extract info for each product
    for product in results:
        name = product.xpath('//*[@class="s-item__link"]').extract_first()[30:124]

        yield {"Name":name,}