如何用Python漂亮地打印ASCII表？

时间：2011-05-06 10:09:21

标签： python ascii tabular

我正在寻找一种漂亮打印这样的表的方法：

=======================
| column 1 | column 2 |
=======================
| value1   | value2   |
| value3   | value4   |
=======================

我找到了asciitable库，但它没有做边框等。我不需要任何复杂的数据项格式，它们只是字符串。我确实需要它来自动调整列数。

是否存在其他库或方法，或者我需要花几分钟时间自己编写？

13 个答案:

答案 0 :(得分：43)

我很久以前就已经读过这个问题，并为桌子编写了自己的漂亮打印机：tabulate。

我的用例是：

  • 我大部分时间都想要一个班轮
  • 非常聪明，能够为我找到最佳格式
  • 并可以输出不同的纯文本格式

根据您的示例，grid可能是最相似的输出格式：

from tabulate import tabulate
print tabulate([["value1", "value2"], ["value3", "value4"]], ["column 1", "column 2"], tablefmt="grid")
+------------+------------+
| column 1   | column 2   |
+============+============+
| value1     | value2     |
+------------+------------+
| value3     | value4     |
+------------+------------+

其他支持的格式为plain（无行），simple（Pandoc简单表），pipe（如PHP Markdown Extra中的表格），orgtbl（如表格）在Emacs的org-mode中，rst（就像reStructuredText中的简单表一样）。可以在Emacs中轻松编辑grid和orgtbl。

在性能方面，tabulate略慢于asciitable，但比PrettyTable和texttable快得多。

P.S。我也是调整数字by a decimal column的忠实粉丝。因此，如果有任何（可覆盖的），这是数字的默认对齐方式。

答案 1 :(得分：37)

这是一个快速而肮脏的小函数，我编写的用于显示SQL查询的结果，我只能通过SOAP API。它期望输入一个或多个namedtuples的序列作为表行。如果只有一条记录，则会以不同方式打印出来。

对我来说很方便，可以成为你的起点：

def pprinttable(rows):
  if len(rows) > 1:
    headers = rows[0]._fields
    lens = []
    for i in range(len(rows[0])):
      lens.append(len(max([x[i] for x in rows] + [headers[i]],key=lambda x:len(str(x)))))
    formats = []
    hformats = []
    for i in range(len(rows[0])):
      if isinstance(rows[0][i], int):
        formats.append("%%%dd" % lens[i])
      else:
        formats.append("%%-%ds" % lens[i])
      hformats.append("%%-%ds" % lens[i])
    pattern = " | ".join(formats)
    hpattern = " | ".join(hformats)
    separator = "-+-".join(['-' * n for n in lens])
    print hpattern % tuple(headers)
    print separator
    _u = lambda t: t.decode('UTF-8', 'replace') if isinstance(t, str) else t
    for line in rows:
        print pattern % tuple(_u(t) for t in line)
  elif len(rows) == 1:
    row = rows[0]
    hwidth = len(max(row._fields,key=lambda x: len(x)))
    for i in range(len(row)):
      print "%*s = %s" % (hwidth,row._fields[i],row[i])

示例输出：

pkid                                 | fkn                                  | npi
-------------------------------------+--------------------------------------+----
405fd665-0a2f-4f69-7320-be01201752ec | 8c9949b9-552e-e448-64e2-74292834c73e | 0
5b517507-2a42-ad2e-98dc-8c9ac6152afa | f972bee7-f5a4-8532-c4e5-2e82897b10f6 | 0
2f960dfc-b67a-26be-d1b3-9b105535e0a8 | ec3e1058-8840-c9f2-3b25-2488f8b3a8af | 1
c71b28a3-5299-7f4d-f27a-7ad8aeadafe0 | 72d25703-4735-310b-2e06-ff76af1e45ed | 0
3b0a5021-a52b-9ba0-1439-d5aafcf348e7 | d81bb78a-d984-e957-034d-87434acb4e97 | 1
96c36bb7-c4f4-2787-ada8-4aadc17d1123 | c171fe85-33e2-6481-0791-2922267e8777 | 1
95d0f85f-71da-bb9a-2d80-fe27f7c02fe2 | 226f964c-028d-d6de-bf6c-688d2908c5ae | 1
132aa774-42e5-3d3f-498b-50b44a89d401 | 44e31f89-d089-8afc-f4b1-ada051c01474 | 1
ff91641a-5802-be02-bece-79bca993fdbc | 33d8294a-053d-6ab4-94d4-890b47fcf70d | 1
f3196e15-5b61-e92d-e717-f00ed93fe8ae | 62fa4566-5ca2-4a36-f872-4d00f7abadcf | 1

实施例

>>> from collections import namedtuple
>>> Row = namedtuple('Row',['first','second','third'])
>>> data = Row(1,2,3)
>>> data
Row(first=1, second=2, third=3)
>>> pprinttable([data])
 first = 1
second = 2
 third = 3
>>> pprinttable([data,data])
first | second | third
------+--------+------
    1 |      2 |     3
    1 |      2 |     3

答案 2 :(得分：18)

出于某些原因，当我在谷歌搜索中加入'docutils'时，我偶然发现texttable，这似乎是我正在寻找的。

答案 3 :(得分：12)

我也写了我自己的解决方案。我试着保持简单。

https://github.com/Robpol86/terminaltables 

from terminaltables import AsciiTable
table_data = [
    ['Heading1', 'Heading2'],
    ['row1 column1', 'row1 column2'],
    ['row2 column1', 'row2 column2']
]
table = AsciiTable(table_data)
print table.table
+--------------+--------------+
| Heading1     | Heading2     |
+--------------+--------------+
| row1 column1 | row1 column2 |
| row2 column1 | row2 column2 |
+--------------+--------------+

table.inner_heading_row_border = False
print table.table
+--------------+--------------+
| Heading1     | Heading2     |
| row1 column1 | row1 column2 |
| row2 column1 | row2 column2 |
+--------------+--------------+

table.inner_row_border = True
table.justify_columns[1] = 'right'
table.table_data[1][1] += '\nnewline'
print table.table
+--------------+--------------+
| Heading1     |     Heading2 |
+--------------+--------------+
| row1 column1 | row1 column2 |
|              |      newline |
+--------------+--------------+
| row2 column1 | row2 column2 |
+--------------+--------------+

答案 4 :(得分：5)

使用w3m设计的版本可以处理MattH版本接受的类型：

import subprocess
import tempfile
import html
def pprinttable(rows):
    esc = lambda x: html.escape(str(x))
    sour = "<table border=1>"
    if len(rows) == 1:
        for i in range(len(rows[0]._fields)):
            sour += "<tr><th>%s<td>%s" % (esc(rows[0]._fields[i]), esc(rows[0][i]))
    else:
        sour += "<tr>" + "".join(["<th>%s" % esc(x) for x in rows[0]._fields])
        sour += "".join(["<tr>%s" % "".join(["<td>%s" % esc(y) for y in x]) for x in rows])
    with tempfile.NamedTemporaryFile(suffix=".html") as f:
        f.write(sour.encode("utf-8"))
        f.flush()
        print(
            subprocess
            .Popen(["w3m","-dump",f.name], stdout=subprocess.PIPE)
            .communicate()[0].decode("utf-8").strip()
        )

from collections import namedtuple
Row = namedtuple('Row',['first','second','third'])
data1 = Row(1,2,3)
data2 = Row(4,5,6)
pprinttable([data1])
pprinttable([data1,data2])

结果：

┌───────┬─┐
│ first │1│
├───────┼─┤
│second │2│
├───────┼─┤
│ third │3│
└───────┴─┘
┌─────┬───────┬─────┐
│first│second │third│
├─────┼───────┼─────┤
│1    │2      │3    │
├─────┼───────┼─────┤
│4    │5      │6    │
└─────┴───────┴─────┘

答案 5 :(得分：4)

如果您想要一个包含列和行跨度的表，请尝试我的库dashtable 

from dashtable import data2rst

table = [
        ["Header 1", "Header 2", "Header3", "Header 4"],
        ["row 1", "column 2", "column 3", "column 4"],
        ["row 2", "Cells span columns.", "", ""],
        ["row 3", "Cells\nspan rows.", "- Cells\n- contain\n- blocks", ""],
        ["row 4", "", "", ""]
    ]

# [Row, Column] pairs of merged cells
span0 = ([2, 1], [2, 2], [2, 3])
span1 = ([3, 1], [4, 1])
span2 = ([3, 3], [3, 2], [4, 2], [4, 3])

my_spans = [span0, span1, span2]

print(data2rst(table, spans=my_spans, use_headers=True))

哪个输出：

+----------+------------+----------+----------+
| Header 1 | Header 2   | Header3  | Header 4 |
+==========+============+==========+==========+
| row 1    | column 2   | column 3 | column 4 |
+----------+------------+----------+----------+
| row 2    | Cells span columns.              |
+----------+----------------------------------+
| row 3    | Cells      | - Cells             |
+----------+ span rows. | - contain           |
| row 4    |            | - blocks            |
+----------+------------+---------------------+

答案 6 :(得分：3)

您可以尝试BeautifulTable。它做你想做的事。以下是documentation

的示例 
>>> from beautifultable import BeautifulTable
>>> table = BeautifulTable()
>>> table.column_headers = ["name", "rank", "gender"]
>>> table.append_row(["Jacob", 1, "boy"])
>>> table.append_row(["Isabella", 1, "girl"])
>>> table.append_row(["Ethan", 2, "boy"])
>>> table.append_row(["Sophia", 2, "girl"])
>>> table.append_row(["Michael", 3, "boy"])
>>> print(table)
+----------+------+--------+
|   name   | rank | gender |
+----------+------+--------+
|  Jacob   |  1   |  boy   |
+----------+------+--------+
| Isabella |  1   |  girl  |
+----------+------+--------+
|  Ethan   |  2   |  boy   |
+----------+------+--------+
|  Sophia  |  2   |  girl  |
+----------+------+--------+
| Michael  |  3   |  boy   |
+----------+------+--------+

答案 7 :(得分：2)

我知道这个问题有点老了，但这是我的尝试：

https://gist.github.com/lonetwin/4721748

它有点可读性恕我直言（虽然它没有像@ MattH的解决方案那样区分单行/多行，也没有使用NamedTuples）。

答案 8 :(得分：2)

我使用这个小实用功能。

def get_pretty_table(iterable, header):
    max_len = [len(x) for x in header]
    for row in iterable:
        row = [row] if type(row) not in (list, tuple) else row
        for index, col in enumerate(row):
            if max_len[index] < len(str(col)):
                max_len[index] = len(str(col))
    output = '-' * (sum(max_len) + 1) + '\n'
    output += '|' + ''.join([h + ' ' * (l - len(h)) + '|' for h, l in zip(header, max_len)]) + '\n'
    output += '-' * (sum(max_len) + 1) + '\n'
    for row in iterable:
        row = [row] if type(row) not in (list, tuple) else row
        output += '|' + ''.join([str(c) + ' ' * (l - len(str(c))) + '|' for c, l in zip(row, max_len)]) + '\n'
    output += '-' * (sum(max_len) + 1) + '\n'
    return output

print get_pretty_table([[1, 2], [3, 4]], ['header 1', 'header 2'])

输出

-----------------
|header 1|header 2|
-----------------
|1       |2       |
|3       |4       |
-----------------

答案 9 :(得分：1)

这是我的解决方案：

Map<MatrixXd>

答案 10 :(得分：0)

这可以通过使用列表和字符串理解相当紧凑地使用内置模块来完成。接受所有相同格式的词典列表...... 

def tableit(dictlist):
    lengths = [ max(map(lambda x:len(x.get(k)), dictlist) + [len(k)]) for k in dictlist[0].keys() ]
    lenstr = " | ".join("{:<%s}" % m for m in lengths)
    lenstr += "\n"

    outmsg = lenstr.format(*dictlist[0].keys())
    outmsg += "-" * (sum(lengths) + 3*len(lengths))
    outmsg += "\n"
    outmsg += "".join(
        lenstr.format(*v) for v in [ item.values() for item in dictlist ]
    )
    return outmsg

答案 11 :(得分：0)

from sys import stderr, stdout    
def create_table(table: dict, full_row: bool = False) -> None:

        min_len = len(min((v for v in table.values()), key=lambda q: len(q)))
        max_len = len(max((v for v in table.values()), key=lambda q: len(q)))

        if min_len < max_len:
            stderr.write("Table is out of shape, please make sure all columns have the same length.")
            stderr.flush()
            return

        additional_spacing = 1

        heading_separator = '| '
        horizontal_split = '| '

        rc_separator = ''
        key_list = list(table.keys())
        rc_len_values = []
        for key in key_list:
            rc_len = len(max((v for v in table[key]), key=lambda q: len(str(q))))
            rc_len_values += ([rc_len, [key]] for n in range(len(table[key])))

            heading_line = (key + (" " * (rc_len + (additional_spacing + 1)))) + heading_separator
            stdout.write(heading_line)

            rc_separator += ("-" * (len(key) + (rc_len + (additional_spacing + 1)))) + '+-'

            if key is key_list[-1]:
                stdout.flush()
                stdout.write('\n' + rc_separator + '\n')

        value_list = [v for vl in table.values() for v in vl]

        aligned_data_offset = max_len

        row_count = len(key_list)

        next_idx = 0
        newline_indicator = 0
        iterations = 0

        for n in range(len(value_list)):
            key = rc_len_values[next_idx][1][0]
            rc_len = rc_len_values[next_idx][0]

            line = ('{:{}} ' + " " * len(key)).format(value_list[next_idx], str(rc_len + additional_spacing)) + horizontal_split

            if next_idx >= (len(value_list) - aligned_data_offset):
                next_idx = iterations + 1
                iterations += 1
            else:
                next_idx += aligned_data_offset

            if newline_indicator >= row_count:
                if full_row:
                    stdout.flush()
                    stdout.write('\n' + rc_separator + '\n')
                else:
                    stdout.flush()
                    stdout.write('\n')

                newline_indicator = 0

            stdout.write(line)
            newline_indicator += 1

        stdout.write('\n' + rc_separator + '\n')
        stdout.flush()

示例：

table = {
        "uid": ["0", "1", "2", "3"],
        "name": ["Jon", "Doe", "Lemma", "Hemma"]
    }

create_table(table)

输出：

uid   | name       | 
------+------------+-
0     | Jon        | 
1     | Doe        | 
2     | Lemma      | 
3     | Hemma      | 
------+------------+-

答案 12 :(得分：0)

我刚刚发布了asciiplotlib，它也有漂亮的表格。例如，

import asciiplotlib as apl

data = [
    [["a", "bb", "ccc"]],
    [[1, 2, 3], [613.23236243236, 613.23236243236, 613.23236243236]],
]

fig = apl.figure()
fig.table(data, border_style="thin", ascii_mode=True, padding=(0, 1), alignment="lcr")
fig.show()

得到你

+-----------------+-----------------+-----------------+
| a               |       bb        |             ccc |
+=================+=================+=================+
| 1               |        2        |               3 |
+-----------------+-----------------+-----------------+
| 613.23236243236 | 613.23236243236 | 613.23236243236 |
+-----------------+-----------------+-----------------+

默认情况下，表格以Unicode box-drawing characters呈现，

┌─────────────────┬─────────────────┬─────────────────┐
│ a               │ bb              │ ccc             │
╞═════════════════╪═════════════════╪═════════════════╡
│ 1               │ 2               │ 3               │
├─────────────────┼─────────────────┼─────────────────┤
│ 613.23236243236 │ 613.23236243236 │ 613.23236243236 │
└─────────────────┴─────────────────┴─────────────────┘

apl的表是非常可配置的。查看the tests以获得更多示例。

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