Question

在MS SQL中，如何计算两个日期之间的时间，不包括晚上6点至晚上8点以及周末的晚上/晚上（非工作时间）的时间？

示例：

第1列：Time1: 2019-11-28 16:30:00

第2列：Time2: 2019-11-29 09:00:00

计算出的差异：1.5 h + 1 h = 2.5 h

Answer 1

尝试一下：

declare @Column1 as smalldatetime, @Column2 as smalldatetime, @Column as smalldatetime
set @Column1 = '2019-11-28 16:30:00'
set @Column2 = '2019-11-29 09:00:00'

set @Column = @Column2

select 
case 
when DATEPART(DW, @Column) in (1, 7) then 0
when  @Column <= dateadd(hour,18,cast(cast(@Column as date) as smalldatetime)) and @Column > dateadd(hour,9,cast(cast(@Column as date) as smalldatetime))
then datediff(minute, @Column, dateadd(hour,18,cast(cast(@Column as date) as smalldatetime)))

when @Column >= dateadd(hour,8,cast(cast(@Column as date) as smalldatetime)) and @Column < dateadd(hour,18,cast(cast(@Column as date) as smalldatetime))
then datediff(minute, dateadd(hour,8,cast(cast(@Column as date) as smalldatetime)), @Column)

end

Answer 2

这是一个使用临时提示表的选项

CROSS APPLY将返回营业秒数，然后格式化就变得无关紧要。注意：您必须为24小时以上的物品留出余量。

示例

Declare @YourTable table (ID int,DT1 datetime,DT2 datetime)
Insert Into @YourTable values
(1,'2019-11-28 16:30:00','2019-11-29 09:00:00')

Select A.*
      ,Elapsed=format(dateadd(SECOND,Seconds,0),'HH:mm')
 From  @YourTable A
 Cross Apply (
                Select Seconds=sum(1)
                 From (Select Top (DateDiff(SECOND,DT1,DT2)+1) D=DateAdd(SECOND,-1+Row_Number() Over (Order By (Select Null)),DT1) From  master..spt_values n1,master..spt_values n2) A
                 Where DateName(WEEKDAY,D) not in ('Saturday','Sunday')
                  and  convert(time,D) > '08:00' 
                  and  convert(time,D) < '18:00'  
             ) B

返回

ID  DT1                        DT2                      Elapsed
1   2019-11-28 16:30:00.000    2019-11-29 09:00:00.000  02:30

两个日期之间的时间（晚上和周末除外）？

2 个答案: