使用单个SQL语句检索两个COUNT

Question

假设Table1具有c1列，其允许值为1或0.

如何使用单个查询检索0，1的数量？有可能吗？

抱歉，STUPID的提问方式。

我想把答案放在一行，而不是单列。

Answer 1

这是单个表/索引读取。子查询很可能有两个这样的读取

SELECT
   COUNT(CASE status WHEN 1 THEN 1 ELSE NULL END) AS Ones,
   COUNT(CASE status WHEN 0 THEN 1 ELSE NULL END) AS Zeros
FROM
   MyTable

..它也是便携式的

Answer 2

如果我理解正确，只需GROUP BY该列。

SELECT c1, count(*)
FROM Table1
GROUP BY c1;

Answer 3

替代方式;

select
   sum(c1) as ones, 
   count(*) - sum(c1) as zeros
from
   Table1

Answer 4

取决于您正在使用的DBMS。 在oracle中，以下是可能的：

select
 (select count(status) from table1 where status = 0) as status_0,
 (select count(status) from table1 where status = 1) as status_1
from dual

Answer 5

已经回答过，但总有（几乎）不止一种方法可以做到这一点。两个查询的联盟？

select count(*) from t1 where value='0' 
union
select count(*) from t1 where value='1' 

Answer 6

  

从emp

中选择uid      

UID 0 0 0 1 1 1 1 0 0

select distinct

(select count(uid) from emp  where uid = 0) zeros_total,

(select count(uid) from emp where uid = 1) ones_total

from 
emp

<强> O / P ** zeros_total 5 ones_total 4 **