获取驱动器空间

Question

如果缓存目录变得太大，我每天都会通过CRON编写一个小脚本来清除我的linux上的空间。由于我真的很喜欢bash脚本，所以我需要你的linux专家的一些帮助。

这基本上是逻辑（伪代码）

    if ( Drive Space Left < 5GB )
    {
        change directory to '/home/user/lotsa_cache_files/'

        if ( current working directory = '/home/user/lotsa_cache_files/')
        {
            delete files in /home/user/lotsa_cache_files/
        }
    }

获取驱动器空间

我打算从'/ dev / sda5'命令中获取驱动器空间。如果您的信息返回以下值：

Filesystem           1K-blocks      Used Available Use% Mounted on<br>
/dev/sda5            225981844 202987200  11330252  95% /

因此可能需要一点正则表达式来使'11330252'超出返回值

一点偏执狂

'if（当前工作目录= / home / user / lotsa_cache_files /）'部分只是我内心偏执的防御机制。我想确保我确实在'/ home / user / lotsa_cache_files /'之前我继续执行删除命令，如果当前工作目录由于某种原因不存在则可能具有破坏性。

删除文件

删除文件将使用以下命令而不是通常的rm -f：

完成

find . -name "*" -print | xargs rm

这是因为Linux系统固有的无法“rm”目录，如果它包含太多文件，正如我过去所了解的那样。

Answer 1

另一个提案（代码内的评论）：

FILESYSTEM=/dev/sda1 # or whatever filesystem to monitor
CAPACITY=95 # delete if FS is over 95% of usage 
CACHEDIR=/home/user/lotsa_cache_files/

# Proceed if filesystem capacity is over than the value of CAPACITY (using df POSIX syntax)
# using [ instead of [[ for better error handling.
if [ $(df -P $FILESYSTEM | awk '{ gsub("%",""); capacity = $5 }; END { print capacity }') -gt $CAPACITY ]
then
    # lets do some secure removal (if $CACHEDIR is empty or is not a directory find will exit
    # with error which is quite safe for missruns.):
    find "$CACHEDIR" --maxdepth 1 --type f -exec rm -f {} \;
    # remove "maxdepth and type" if you want to do a recursive removal of files and dirs
    find "$CACHEDIR" -exec rm -f {} \;
fi

从crontab调用脚本进行计划清理

Answer 2

我会这样做：

# get the available space left on the device
size=$(df -k /dev/sda5 | tail -1 | awk '{print $4}')

# check if the available space is smaller than 5GB (5000000kB)
if (($size<5000000)); then
  # find all files under /home/user/lotsa_cache_files and delete them
  find /home/user/lotsa_cache_files -name "*" -delete
fi

Answer 3

这是我用来删除目录中的旧文件以释放空间的脚本......

#!/bin/bash
#
#  prune_dir - prune directory by deleting files if we are low on space
#
DIR=$1
CAPACITY_LIMIT=$2

if [ "$DIR" == "" ]
then
    echo "ERROR: directory not specified"
    exit 1
fi

if ! cd $DIR
then
    echo "ERROR: unable to chdir to directory '$DIR'"
    exit 2
fi

if [ "$CAPACITY_LIMIT" == "" ]
then
    CAPACITY_LIMIT=95   # default limit
fi

CAPACITY=$(df -k . | awk '{gsub("%",""); capacity=$5}; END {print capacity}')

if [ $CAPACITY -gt $CAPACITY_LIMIT ]
then
    #
    # Get list of files, oldest first.
    # Delete the oldest files until
    # we are below the limit. Just
    # delete regular files, ignore directories.
    #
    ls -rt | while read FILE
    do
        if [ -f $FILE ]
        then
            if rm -f $FILE
            then
                echo "Deleted $FILE"

                CAPACITY=$(df -k . | awk '{gsub("%",""); capacity=$5}; END {print capacity}')

                if [ $CAPACITY -le $CAPACITY_LIMIT ]
                then
                    # we're below the limit, so stop deleting
                    exit
                fi
            fi
        fi
    done
fi

Answer 4

要检测文件系统的占用情况，我使用：

df -k $FILESYSTEM | tail -1 | awk '{print $5}'

它给了我文件系统的占用百分比，这样，我不需要计算它：）

如果你使用bash，你可以使用pushd / popd操作来更改目录，并确保进入。

pushd '/home/user/lotsa_cache_files/'
do the stuff
popd

Answer 5

这就是我所做的：

while read f; do rm -rf ${f}; done < movies-to-delete.txt

用于在磁盘已满时删除文件的Shell脚本

获取驱动器空间

一点偏执狂

删除文件

5 个答案: