这是我的学校作业,无论验证码输入是真还是假,它始终返回true,并将用户引导到首页。我不知道我做错了什么部分导致了这个错误
<?php
session_start();
include 'koneksi.php';
$username = $_POST['username'];
$pass= $_POST['pass'];
$captcha = $_POST['nilaicaptcha'];
$result = mysqli_query($koneksi,"select username,password from acc where username='$username' and password='$pass'");
if(isset($_POST['sigin'])){
if (!isset($username) or !isset($pass)){
echo "Username or Password is invalid";
}
else if (mysqli_num_rows($result)>0 and $captcha==$_SESSION['captcha']){
$_SESSION['login_user'] = $username;
header("location:home.php");
}
else {
echo "Salah";
echo "Username or Password is invalid";
}
exit;
}
else if(isset($_POST['register'])){
header("location:register.php");
}
?>
我已经检查了变量是否正确,没有类型错误或错误传递的变量。我认为这与$captcha==$_SESSION['captcha']
部分有关,但是我不确定为什么这是错误的,因为对我来说似乎不错,而也许不是这样
答案 0 :(得分:0)
感谢帮助人员,我发现问题出在操作员身上。应该是else if (mysqli_num_rows($result)>0 and $_SESSION['Captcha']===$captcha)
答案 1 :(得分:-1)