如何在Flutter中的步进器上传递列表

时间:2019-11-27 08:48:49

标签: flutter flutter-layout

我正在使用Stepper创建App,但是在Stepper中传递列表时出现错误

类似的东西:未定义命名参数“ steps”

我的代码:

class Stepper extends StatefulWidget {
  @override
  _StateStepper createState() => _StateStepper();
}

class _StateStepper extends State<Stepper> {

  List<Step> my_steps = [
    new Step(title: Text("Step 1"), content: Text("Some Content")),
    new Step(title: Text("Step 2"), content: Text("Some Content")),
    new Step(title: Text("Step 3"), content: Text("Some Content")),
    new Step(title: Text("Step 4"), content: Text("Some Content")),
  ];


  @override
  Widget build(BuildContext context) {
    return Scaffold(
      appBar: new AppBar(
        title: Text("Util App"),
      ),
      body: Container(
       child: Stepper(steps:my_steps),
      ),
    );
  }
}

2 个答案:

答案 0 :(得分:2)

class MyStepper extends StatefulWidget {
  @override
 _StateStepper createState() => _StateStepper();
}

class _StateStepper extends State<Stepper> {

List<Step> my_steps = [
    new Step(title: Text("Step 1"), content: Text("Some Content")),
    new Step(title: Text("Step 2"), content: Text("Some Content")),
    new Step(title: Text("Step 3"), content: Text("Some Content")),
    new Step(title: Text("Step 4"), content: Text("Some Content")),
];


@override
Widget build(BuildContext context) {
    return Scaffold(
      appBar: new AppBar(
        title: Text("Util App"),
      ),
      body: Container(
       child: Stepper(steps:my_steps),
       ),
     );
   }
}

答案 1 :(得分:1)

  

Stepperflutter/material package中的类,因此请避免在应用程序中使用保留名称或使用的类名称。