我有如下所示的“待办事项列表”。 我想在“ Argent Level”,“所需时间”和“ Incoming order”之后排列“ TO-DO LIST”,不使用sort()函数
# "Argent Level", "The time required" and "Incoming order"
work_list = [
"Low_Level, 1, A.Login Error",
"High_Level, 3, B.User info Error",
"Nomal_Level, 1, C.Admin Error",
"Low_Level, 2, D.Icon change of User",
"High_Level, 3, E.Email export Error",
"Nomal_Level, 1, F.Photo size Error",
"High_Level, 2, G.Admin Page Error",
"Nomal_Level, 3, H.Customer Page Error",
"Low_Level, 1, I.Image box Error",
"Nomal_Level, 3, J.Border Error",
"Low_Level, 1, K.Background Color Error",
"High_Level, 2, L.SignUp Error",
]
例如,有相同的“高级”列表,如下所示。
"High_Level, 3, B.User info Error",
"High_Level, 3, E.Email export Error",
"High_Level, 2, G.Admin Page Error",
"High_Level, 2, L.SignUp Error",
首先,我想按“所需时间”按以下顺序排列此列表,如果它们具有相同的“所需时间”,则按大写字母使用“来料顺序”按进货顺序进行下一张订单
"High_Level, 2, G.Admin Page Error",
"High_Level, 2, L.SignUp Error",
"High_Level, 3, B.User info Error",
"High_Level, 3, E.Email export Error",
我试图制作这样的代码。但这是不正确的。
high_level_list = []
nomal_level_list = []
low_level_list = []
for i in range(0, len(work_list)):
if "High_Level" in work_list[i]:
high_level_list.append(work_list[i])
for i in range(0, len(work_list)):
if "Nomal_Level" in work_list[i]:
nomal_level_list.append(work_list[i])
for i in range(0, len(work_list)):
if "Low_Level" in work_list[i]:
low_level_list.append(work_list[i])
for i in range(0, len(high_level_list)):
if high_level_list[i][1] >= 3:
temp = high_level_list[-1]
high_level_list[-1] = high_level_list[i]
high_level_list[i] = temp
print(high_level_list)
我想输出如下
"High_Level, 2, G.Admin Page Error",
"High_Level, 2, L.SignUp Error",
"High_Level, 3, B.User info Error",
"High_Level, 3, E.Email export Error",
"Nomal_Level, 1, C.Admin Error",
"Nomal_Level, 1, F.Photo size Error",
"Nomal_Level, 3, H.Customer Page Error",
"Nomal_Level, 3, J.Border Error",
"Low_Level, 1, A.Login Error",
"Low_Level, 1, I.Image box Error",
"Low_Level, 1, K.Background Color Error",
"Low_Level, 2, D.Icon change of User",
答案 0 :(得分:1)
首先,您需要将work_list
转换为元组列表,而不只是字符串,以便可以访问各个字段,尤其是最后一步中需要的数字。
>>> work_list_tuples = [tuple(s.split(", ")) for s in work_list]
您的第一个循环应该可以工作,但是您可以根据列表理解使它们更紧凑
>>> high = [x for x in work_list_tuples if x[0] == "High_Level"]
您的最后一个循环是一种错误的插入排序,但是您可以尝试使用另一种列表理解来过滤值也为3或更高的high
项,而不是试图解决该问题:
>>> high_3 = [x for x in high if int(x[1]) >= 3]
这给你
[('High_Level', '3', 'B.User info Error'),
('High_Level', '3', 'E.Email export Error')]
对normal
和low
级别以及低于3的high
进行相同的操作,然后将列表放在一起。
>>> high_3 + high_12 + norm + low
[('High_Level', '3', 'B.User info Error'),
...
('High_Level', '2', 'L.SignUp Error'),
...
('Nomal_Level', '1', 'C.Admin Error'),
...
('Low_Level', '1', 'K.Background Color Error')]
但是,在所有远程实际应用中,我强烈建议仅将sort
(列表方法)或sorted
(内置函数)与适当的键功能一起使用,例如像这样:
>>> sorted(work_list_tuples, key=lambda x: ("HNL".index(x[0][0]), -int(x[1])))
[('High_Level', '3', 'B.User info Error'),
('High_Level', '3', 'E.Email export Error'),
('High_Level', '2', 'G.Admin Page Error'),
('High_Level', '2', 'L.SignUp Error'),
('Nomal_Level', '3', 'H.Customer Page Error'),
('Nomal_Level', '3', 'J.Border Error'),
('Nomal_Level', '1', 'C.Admin Error'),
('Nomal_Level', '1', 'F.Photo size Error'),
('Low_Level', '2', 'D.Icon change of User'),
('Low_Level', '1', 'A.Login Error'),
('Low_Level', '1', 'I.Image box Error'),
('Low_Level', '1', 'K.Background Color Error')]