Question

我希望遍历array的{{1}}，为便于说明，此处为objects。我想使用提供的搜索词和每个Users属性的值来过滤那些Users。

我想出了以下可行的解决方案，但是，我想看看是否有人有更优雅的方法？

objects

[编辑]

我不对对象上任何字段的结构，名称或数量做任何假设，因此，我不想使用诸如let users = [ { first_name: "Super", last_name: "User" }, { first_name: "Admin", last_name: "Istrator" } ]; function filterObjects(collection, term) { let filtered = []; _.each(collection, obj => { _.forOwn(obj, (value, key) => { if (value.includes(term)) { filtered.push(obj); } }); }); return filtered; } console.log(filterUsers(users, "Su"));之类的东西。

Answer 1

您可以过滤并使用_.some()来迭代值，并使用Array.includes()（或等效的破折号）检查值中是否存在该术语。

const filterUsers = (collection, term) =>
  collection.filter(o => _.some(o, v => v.includes(term)));

const users = [{"first_name":"Super","last_name":"User"},{"first_name":"Admin","last_name":"Istrator"}];

console.log(filterUsers(users, "Su"));

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.15/lodash.js"></script>

和使用lodash/fp的想法相同：

const { filter, some, includes } = _;

const filterUsers = term => filter(some(includes(term)));

const users = [{"first_name":"Super","last_name":"User"},{"first_name":"Admin","last_name":"Istrator"}];

console.log(filterUsers("Su")(users));

<script src='https://cdn.jsdelivr.net/g/lodash@4(lodash.min.js+lodash.fp.min.js)'></script>

Answer 2

没有第三方库的解决方案可能是：

var term = 'Su';
var filtered = users.filter(({first_name, last_name}) => {
 return (first_name.includes(term) || last_name.includes(term));
});

console.log(filtered);

希望对您有帮助。

按值过滤对象数组

2 个答案: