我想从其他来源抓取新闻。我找到了一种生成网址以从Google抓取多个页面的方法,但是我认为有一种方法可以生成更短的链接。
能否请您告诉我如何生成用于抓取Bing和Yahoo新闻的多个页面的URL,并且还有一种方法可以使Google网址更短。
这是google的代码:
from bs4 import BeautifulSoup
import requests
headers = {'User-Agent':'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/47.0.2526.106 Safari/537.36'}
term = 'usa'
page=0
for page in range(1,5):
page = page*10
url = 'https://www.google.com/search?q={}&tbm=nws&sxsrf=ACYBGNTx2Ew_5d5HsCvjwDoo5SC4U6JBVg:1574261023484&ei=H1HVXf-fHfiU1fAP65K6uAU&start={}&sa=N&ved=0ahUKEwi_q9qog_nlAhV4ShUIHWuJDlcQ8tMDCF8&biw=1280&bih=561&dpr=1.5'.format(term,page)
print(url)
response = requests.get(url, headers=headers)
soup = BeautifulSoup(response.text, 'html.parser')
这些是yahoo和bing的URL,但只有1页:
yahoo:url = 'https://news.search.yahoo.com/search?q={}'.format(term)
bing:url = 'https://www.bing.com/news/search?q={}'.format(term)
答案 0 :(得分:1)
我不确定您是否正在寻找这个简短的新闻网址。
let array = [1, 3, 3, 3, 5, 5, 5, 5, 5, 5, 7];
console.log(binarySearch(array, 0)); // Gives [ -1, 0 ] <= No value found, note that resulting range covers area beyond array boundaries
console.log(binarySearch(array, 1)); // Gives [ 0, 0 ] <= Singular range (only one value found)
console.log(binarySearch(array, 2)); // Gives [ 0, 1 ] <= Queried value not found, however the range covers argument value
console.log(binarySearch(array, 3)); // Gives [ 1, 3 ] <= Multiple values found
console.log(binarySearch(array, 4)); // Gives [ 3, 4 ] <= Queried value not found, however the range covers argument value
console.log(binarySearch(array, 5)); // Gives [ 4, 9 ] <= Multiple values found
console.log(binarySearch(array, 6)); // Gives [ 9, 10 ] <= Queried value not found, however the range covers argument value
console.log(binarySearch(array, 7)); // Gives [ 10, 10 ] <= Singular range (only one value found)
console.log(binarySearch(array, 8)); // Gives [ 10, 11 ] <= No value found, note that resulting range covers area beyond array boundaries
#Yahoo:
from bs4 import BeautifulSoup
import requests
headers = {'User-Agent':'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/47.0.2526.106 Safari/537.36'}
term = 'usa'
page=0
for page in range(1,5):
page = page*10
url = 'https://www.google.com/search?q={}&tbm=nws&start={}'.format(term,page)
print(url)
response = requests.get(url, headers=headers,verify=False)
soup = BeautifulSoup(response.text, 'html.parser')