Question

用于拆分单词

str = "PYTHON IS VERY GOOD LANGUAGE CURRENTLY"
res = str.split(" ",2)
>> output: ["PYTHON", "IS", "VERY GOOD LANGUAGE CURRENTLY"]

但是如果我有这样的输出

output: ["PYTHON","IS VERY","GOOD LANGUAGE CURRENTLY"]

Answer 1

在您的示例中，您似乎想将字符串拆分为包含1个单词，2个单词，3个单词等的子字符串列表。我认为没有内置功能。但是，您可以使用以下代码来实现它：

if __name__ == '__main__':
    str = "PYTHON IS VERY GOOD LANGUAGE CURRENTLY"
    splits = str.split(" ")  # Get string words
    res = []
    s = 0
    i = 0
    while s+1+i <= len(splits):
        res.append(" ".join(splits[s:s+1+i]))  # Make a string with i+1 words starting with word at index s
        # Update your values
        s+=i+1
        i+=1

    print(res)

['PYTHON', 'IS VERY', 'GOOD LANGUAGE CURRENTLY']

根据问题标题和评论者的理解，如果您的预期结果是["PYTHON IS", "VERY GOOD", " LANGUAGE CURRENTLY"]，即由2个单词组成的字符串列表，那么它甚至会更容易。

str = "PYTHON IS VERY GOOD LANGUAGE CURRENTLY"
    splits = str.split(" ")
    # Zip one every two words starting from the beginning
    # with one every two starting from second word
    # leads to a list [(word1, word2), (word3, word4), ...]
    # Join the tuples with a space, and build a list of these new strings
    res = [" ".join(x) for x in zip(splits[::2], splits[1::2])]
    print(res)

['PYTHON IS', 'VERY GOOD', 'LANGUAGE CURRENTLY']

Answer 2

在python split（）函数中，您有2个参数，分隔符和 maxsplit 。因此，如果您指定maxsplit，则只会拆分2，其余的字符串将不会拆分。

Answer 3

您曾经说过split函数只能分裂两次

MAXSPLIT = 2
res = string.split(" ",MAXSPLIT) # Here, we are splitting 2 times.
# ['PYTHON', 'IS', 'VERY GOOD LANGUAGE CURRENTLY']

MAXSPLIT = 3 
res = string.split(" ",3) # Here, we are splitting 3 times.
# ['PYTHON', 'IS', 'VERY', 'GOOD LANGUAGE CURRENTLY']

Answer 4

这是一种稍作复杂的操作，它会产生一个列表列表，但是提取所需的输出并不难。我确定有人知道如何以更明智的方式做到这一点。我只使用str.split（“”）来创建原始字符串中的单词列表。

import numpy as np


def factorial_recursive(n):
    if n == 0:
        return n
    elif n == 1:
        return n
    else:
        return n+factorial_recursive(n-1)


str = "PYTHON IS VERY GOOD LANGUAGE CURRENTLY"
str_lst = str.split(" ")

start = 0
end = 1
output_list = []
for i in range(int(np.floor(len(str_lst)/2))):
    if factorial_recursive(start) >= len(str_lst):
        break
    elif factorial_recursive(end) >= len(str_lst):
        break
    else:
        output_list.append(str_lst[factorial_recursive(start):factorial_recursive(end)])
        start += 1
        end += 1


print(output_list)

分割字符串，中间有2个空格

4 个答案: