Question

我有一个调查相关应用程序表，其中有5个问题都需要Yes（1）或No（0）答案。表格设计如下：

CREATE TABLE score ( project_id int NOT NULL, resp_id int NULL, q1 int, q2 int, q3 int, q4 int, q5 int, );

示例数据：

project_id resp_id q1 q2 q3 q4 q5
1          86      1  1  1  1  1
1          114     1  1  1  1  1
1          118     0  1  1  1  0
2          154     1  1  0  1  1
2          178     1  1  1  0  1
3          182     1  0  1  1  1
3          190     1  1  1  0  1
3          208     1  1  1  1  1
3          300     1  1  1  0  0
3          329     1  1  1  1  1

我需要做的是编写一个查询，生成一个报告，我按项目ID分类，提供0个“是”答案的答复者数量（0个中的0个），1个“是”答案（1个5），2个“是”答案（5个中的2个），等等。换句话说，有多少受访者对所有问题回答“是”，对5个问题中的4个回答是，等等。

可行？任何建议表示赞赏：）

Answer 1

SELECT
  project_ID,
  q1 + q2 + q3 + q4 + q5 AS NumYesAnswers,
  COUNT(*) AS NumResponses
FROM
  score
GROUP BY
  project_ID, q1 + q2 + q3 + q4 + q5

修改

我会将此添加为对Lobo答案的评论，但格式化不起作用。使用PIVOT：

，您可以更优雅地实现相同的效果

SELECT
    Project_ID, "0" AS NoToAll, "1", "2", "3", "4", "5"
FROM
    (
    SELECT Project_ID, Q1 + Q2 + Q3 + Q4 + Q5 AS NumYeses, COUNT(*) AS Answers
    FROM Score
    GROUP BY Project_ID, Q1 + Q2 + Q3 + Q4 + Q5
    ) AS X
PIVOT
    (SUM(Answers) FOR NumYeses IN ("0", "1", "2", "3", "4", "5")) AS Y

Answer 2

所有行业的回答乔恩都很好。此外，如果您不想重复sum语句，请使用CTE（公用表表达式）。

With
ProYes as (
    select project_id,
    q1 + q2 + q3 + q4 + q5 as NumYes
    from score)
select project_id, NumYes, COUNT(*) as NumAnswers
from ProYes
group by project_id, NumYes

Answer 3

-- Be careful about NULL fields(the following is assuming that the q* are NOT NULL fields)
SELECT project_id, 
    SUM(allzeroes) AS NoToAll, SUM(onlyone) AS YesToOne, SUM(two) AS YesToTwo, SUM(three)  AS YesToThree, SUM(four) AS YesToFour, SUM(five) AS YesToAll 
FROM (
    SELECT project_id, 
        (CASE WHEN  (q1 + q2 + q3 + q4 + q5) = 0 THEN COUNT(*) ELSE 0 END) AS allzeroes,
        (CASE WHEN  (q1 + q2 + q3 + q4 + q5) = 1 THEN COUNT(*) ELSE 0 END) AS onlyone,
        (CASE WHEN  (q1 + q2 + q3 + q4 + q5) = 2 THEN COUNT(*) ELSE 0 END) AS two,
        (CASE WHEN  (q1 + q2 + q3 + q4 + q5) = 3 THEN COUNT(*) ELSE 0 END) AS three,
        (CASE WHEN  (q1 + q2 + q3 + q4 + q5) = 4 THEN COUNT(*) ELSE 0 END) AS four,
        (CASE WHEN  (q1 + q2 + q3 + q4 + q5) = 5 THEN COUNT(*) ELSE 0 END) AS five
    FROM score
    GROUP BY project_id, (q1 + q2 + q3 + q4 + q5) ) temp_table
GROUP BY project_id

PS：请更正示例数据头;我无法编辑您的问题。谢谢！

Answer 4

创建一个存储过程并将值设置为变量，然后您可以使用sproc中的select语句并使用where子句有条件地传递它们。

SQL查询 - 计算一组问题的是答案数

4 个答案: