Question

我想将字符串的字母乘以数字的位数。例如，单词“ number”和数字“ 123” 输出将是“ nuummmbeerrr”。如何创建执行此操作的功能？我的代码没有用，因为它不起作用。

我只有这个

def new_word(s):
    b=""
    for i in range(len(s)):
        if i % 2 == 0:
            b = b + s[i] * int(s[i+1])    

return b

对于new_word（'a3n5z1'）输出为 aaannnnnz 。

Answer 1

使用列表推导，不使用itertools：

number = 123
word = "number"

new_word = "".join([character*n for (n, character) in zip(([int(c) for c in str(number)]*len(str(number)))[0:len(word)], word)])

print(new_word)

# > 'nuummmbeerrr'

它的作用（更多细节）如下：

number = 123
word = "number"

# the first trick is to link each character in the word to the number that we want
# for this, we multiply the number as a string and split it so that we get a list...
# ... with length equal to the length of the word
numbers_to_characters = ([int(c) for c in str(number)]*len(str(number)))[0:len(word)]

print(numbers_to_characters)

# > [1, 2, 3, 1, 2, 3]

# then, we initialize an empty list to contain the repeated characters of the new word
repeated_characters_as_list = []

# we loop over each number in numbers_to_letters and each character in the word
for (n, character) in zip(numbers_to_characters, word):
    repeated_characters_as_list.append(character*n)

print(repeated_characters_as_list)

# > ['n', 'uu', 'mmm', 'b', 'ee', 'rrr']

new_word = "".join(repeated_characters_as_list)

print(new_word)

# > 'nuummmbeerrr'

Answer 2

这将解决您的问题，可以随时对其进行修改以满足您的需求。

from itertools import cycle

numbers = cycle("123")
word = "number"

output = []

for letter in word:
  output += [letter for _ in range(int(next(numbers)))]

string_output = ''.join(output)

编辑：

由于您是初学者，即使我建议阅读itertools模块，因为它是处理此类问题的正确工具，但它对您来说更容易理解。

number = "123"
word = "number"


output = []
i = 0

for letter in word:
  if(i == len(number)):
    i = 0
  output += [letter for _ in range(int(number[i]))]
  i += 1

string_output = ''.join(output)
print(string_output)

Answer 3

您可以使用zip将每个数字与单词中的相应字符匹配（对于单词较长的情况，请使用itertools.cycle），然后将char乘以该数字，最后加入到单个字符串。

尝试一下：

from itertools import cycle

word = "number"
number = 123

number_digits = [int(d) for d in str(number)]

result = "".join(letter*num for letter,num in zip(word,cycle(number_digits)))
print(result)

输出：

nuummmbeerrr

字符串字母乘以数字位数

3 个答案: