具有组合主键的OneToOne JPA关系

时间:2019-11-25 14:15:09

标签: java jpa

我有一个双向的OneToOne示例不起作用:

@Embeddable
public class SolicitudGUCDetalleId implements Serializable {

  @Column(name = "IDPEDIDO", insertable = false, updatable = false)
  @Size(max = 36)
  private String idPedido;

  @Column(name = "IDLINEA", precision = 10, scale = 0, insertable = false, updatable = false)
  private long idLinea;

  ...
}

@Entity
@Table(name = "TRIISOLIDGUCDET")
public class SolicitudGUCDetalle implements Serializable {

  @EmbeddedId
  private SolicitudGUCDetalleId id;

  @OneToOne(fetch = FetchType.LAZY, mappedBy = "solicitudGUCDetalle")
  private SolicitudGUCEnvio solicitudGUCEnvio;

  ...
}

@Embeddable
public class SolicitudGUCEnvioId implements Serializable {

  @Column(name = "IDPEDIDO", insertable = false, updatable = false)
  @Size(max = 36)
  private String idPedido;

  @Column(name = "IDLINEA", insertable = false, updatable = false)
  private long idLinea;

  ...
}

@Entity
@Table(name = "TRIISOLIDGUCENV")
public class SolicitudGUCEnvio implements Serializable {


  @EmbeddedId
  private SolicitudGUCEnvioId id;

  @OneToOne(fetch = FetchType.LAZY)
  @PrimaryKeyJoinColumns({
      @PrimaryKeyJoinColumn(name = "IDLINEA", referencedColumnName = "IDLINEA"),
      @PrimaryKeyJoinColumn(name = "IDPEDIDO", referencedColumnName = "IDPEDIDO")})
  private SolicitudGUCDetalle solicitudGUCDetalle;

  ...
}

我已经阅读了有关该问题的信息,并且有两种可行的实现这种关系的方法。

1-对复合主键使用相同的类:

@Embeddable
public class SolicitudGUCId implements Serializable {

  @Column(name = "IDPEDIDO", insertable = false, updatable = false)
  @Size(max = 36)
  private String idPedido;

  @Column(name = "IDLINEA", precision = 10, scale = 0, insertable = false, updatable = false)
  private long idLinea;

  ...
}

@Entity
@Table(name = "TRIISOLIDGUCDET")
public class SolicitudGUCDetalle implements Serializable {

  @EmbeddedId
  private SolicitudGUCId id;

  @OneToOne(fetch = FetchType.LAZY, mappedBy = "solicitudGUCDetalle")
  private SolicitudGUCEnvio solicitudGUCEnvio;

  ...
}

@Entity
@Table(name = "TRIISOLIDGUCENV")
public class SolicitudGUCEnvio implements Serializable {

  @EmbeddedId
  private SolicitudGUCId id;

  @OneToOne(fetch = FetchType.LAZY)
  @PrimaryKeyJoinColumns({
      @PrimaryKeyJoinColumn(name = "IDLINEA", referencedColumnName = "IDLINEA"),
      @PrimaryKeyJoinColumn(name = "IDPEDIDO", referencedColumnName = "IDPEDIDO")})
  private SolicitudGUCDetalle solicitudGUCDetalle;

  ...
}

2-切换到@OneToMany关系并将相关实体存储在Set中:

@Embeddable
public class SolicitudGUCDetalleId implements Serializable {

  @Column(name = "IDPEDIDO", insertable = false, updatable = false)
  @Size(max = 36)
  private String idPedido;

  @Column(name = "IDLINEA", precision = 10, scale = 0, insertable = false, updatable = false)
  private long idLinea;

  ...
}

@Entity
@Table(name = "TRIISOLIDGUCDET")
public class SolicitudGUCDetalle implements Serializable {

  @EmbeddedId
  private SolicitudGUCDetalleId id;

  @OneToMany(fetch = FetchType.LAZY, mappedBy = "solicitudGUCDetalle")
  private Set<SolicitudGUCEnvio> solicitudes;

  ...
}

@Embeddable
public class SolicitudGUCEnvioId implements Serializable {

  @Column(name = "IDPEDIDO", insertable = false, updatable = false)
  @Size(max = 36)
  private String idPedido;

  @Column(name = "IDLINEA", insertable = false, updatable = false)
  private long idLinea;

  ...
}

@Entity
@Table(name = "TRIISOLIDGUCENV")
public class SolicitudGUCEnvio implements Serializable {

  @EmbeddedId
  private SolicitudGUCEnvioId id;

  @ManyToOne(fetch = FetchType.LAZY)
  @JoinColumns({
      @JoinColumn(name = "IDLINEA", referencedColumnName = "IDLINEA",
          nullable = false, insertable = false, updatable = false),
      @JoinColumn(name = "IDPEDIDO", referencedColumnName = "IDPEDIDO",
          nullable = false, insertable = false, updatable = false)})
  private SolicitudGUCDetalle solicitudGUCDetalle;

  ...
}

我想知道我是否可以按照第一个示例实现这种关系。如果答案是否定的,我想知道为什么。

2 个答案:

答案 0 :(得分:1)

这似乎是“派生身份”;因此您可以尝试对选项1进行一些细微改动:

@Embeddable
public class SolicitudGUCId implements Serializable {

    @Column(name = "IDPEDIDO", insertable = false, updatable = false)
    @Size(max = 36)
    private String idPedido;

    @Column(name = "IDLINEA", precision = 10, scale = 0, insertable = false, updatable = false)
    private long idLinea;

    ...
}

@Entity
@Table(name = "TRIISOLIDGUCDET")
public class SolicitudGUCDetalle implements Serializable {

    @EmbeddedId
    private SolicitudGUCId id;

    @OneToOne(fetch = FetchType.LAZY, mappedBy = "solicitudGUCDetalle")
    private SolicitudGUCEnvio solicitudGUCEnvio;

    ...
}

@Entity
@Table(name = "TRIISOLIDGUCENV")
public class SolicitudGUCEnvio implements Serializable {

    @EmbeddedId
    private SolicitudGUCId id;

    @OneToOne(fetch = FetchType.LAZY)
    @JoinColumns({
        @JoinColumn(name = "IDLINEA", referencedColumnName = "IDLINEA"),
        @JoinColumn(name = "IDPEDIDO", referencedColumnName = "IDPEDIDO")})
    @MapsId
    private SolicitudGUCDetalle solicitudGUCDetalle;

    ...
}

请注意,SolicitudGUCEnvio.solicitudGUCDetalle@MapsId@JoinColumns注释(而不是@PrimaryKeyJoinColumns)。

JPA 2.2 spec的第2.4.1节中讨论了派生的身份(带有示例)。

答案 1 :(得分:0)

这是我正在寻找的解决方案:

{field1 => true, field2 => false, field3 => true, field4 => false}

@Brian Vosburgh,谢谢您的帮助