精确的正则表达式与和号匹配

Question

我如何不能仅将“软件”与“软件和框架”相匹配？

$skill = array("software & framework","communication skills","technology-based","software","technology");

$text = "software & framework and technology-based and excel technology- communication";

foreach ($skill as $skills) {

preg_match_all("~(?<![\w-])" . preg_quote($skills) . "(?![\w-])~i", $text, $matchWords);

foreach ($matchWords[0] as $matchWord) {

echo "<b>MatchWord:</b> " . $matchWord.  "<br>";

}

当前结果：

• MatchWord：软件和框架
• MatchWord：基于技术
• MatchWord：软件

预期结果：

• MatchWord：软件和框架
• MatchWord：基于技术

Answer 1

您需要动态构建带有交替的单个模式：

xtl

然后，您可以提取匹配项：

$pattern = '~(?<![\w-])(?:' . implode('|', array_map(function($i) {
     return preg_quote($i, '~');
}, $skill)) . ')(?![\w-])~i';

输出：if (preg_match_all($pattern, $text, $matchWords)) { print_r($matchWords[0]); }

注意：如果Array ([0] => software & framework [1] => technology-based )数组中的迭代没有按长度降序排列，则需要使用以下方法进行预先设置，例如：

$skill

请参见。