Question

我正在使用node.js，express.js构建REST API，但使用数据结构（首先没有数据库）来实现它。我有2条路线Post和Get。我的问题是，我该如何实现get路线，以便能够检索具有作为参数传递的最多技能集的候选人：

这是我的对象

const candidate = [
   {"id":1, "name":"Jonh", "skills":["Python","Java","Go","Node","Express"]},
   {"id":2, "name":"Mary", "skills":["Go","Python"]},
   {"id":3, "name":"Kevin", "skills":["Ruby","Java","Go"]}
   ]

这是get路线：

app.get('candidate/search', function(res,res){

 })

请帮助

Answer 1

您可以按技能对候选人进行排序，然后使用res.json函数返回最熟练的候选人。

skillSortFunction将按技能数降序排序，因此我们要选择排序数组的第一个元素。

const candidate = [
    {"id":1, "name":"Jonh", "skills":["Python","Java","Go","Node","Express"]},
    {"id":2, "name":"Mary", "skills":["Go","Python"]},
    {"id":3, "name":"Kevin", "skills":["Ruby","Java","Go"]}
];

function skillSortFunction(a, b) {
    return (b.skills || []).length - (a.skills || []).length;
}

app.get('candidate/search', function(res,res){
    candidate.sort(skillSortFunction);
    const mostSkilled = candidate[0];
    return res.json(mostSkilled);
})

此处使用原始JavaScript进行演示：

const candidate = [
    {"id":1, "name":"Jonh", "skills":["Python","Java","Go","Node","Express"]},
    {"id":2, "name":"Mary", "skills":["Go","Python"]},
    {"id":3, "name":"Kevin", "skills":["Ruby","Java","Go"]}
];

function skillSortFunction(a, b) {
    return (b.skills || []).length - (a.skills || []).length;
}

candidate.sort(skillSortFunction);
const mostSkilled = candidate[0];
console.log("Most skilled candidate:", mostSkilled);
const leastSkilled = candidate[candidate.length-1];
console.log("Least skilled candidate:", leastSkilled );

根据所传授的技能来寻找具有最高技能的候选人

1 个答案: